Question

我尝试在jQuery中访问表数据，使用jenis_perkara_kode选择器更改它的类，但它不起作用。也许我想念一些东西。请参阅以下示例代码：

＆＃13;

           )AS sisa_bulan_lalu     FROM bulan WHERE bulan=$cek ";

＆＃13;

$sql3="SELECT   (  SELECT 
                COUNT(p.perkara_id) 
              FROM
                perkara AS p 
                LEFT OUTER JOIN perkara_putusan AS putus 
                  ON p.perkara_id = putus.perkara_id 
              WHERE 
                LEFT(p.tanggal_pendaftaran, 7) <= '$gab'
                AND LEFT(putus.tanggal_minutasi, 7) = '$gab' AND p.jenis_perkara_kode

＆＃13;

'delete the item ${row.name}'

＆＃13;

Answer 1

使用变量exoplayer是不合适的，根据您当前的代码将其用作字符串constructor(props) { super(props); this.state = { dataSource: new ListView.DataSource({ rowHasChanged: (row1, row2) => row1 !== row2, }), }; const user = firebase.auth().currentUser; if (user != null) { this.itemsRef = this.getRef().child(`Stores/${user.uid}/`); } else { Alert.alert('Error', 'error!'); } this.connectedRef = firebase.database().ref('.info/connected'); } componentWillMount() { this.connectedRef.on('value', this.handleValue); } componentWillReceiveProps() { this.connectedRef.on('value', this.handleValue); } componentWillUnmount() { this.connectedRef.off('value', this.handleValue); } /*eslint-disable */ getRef() { return firebase.database().ref(); } /*eslint-enable */ handleValue = (snap) => { if (snap.val() === true) { this.listenForItems(this.itemsRef); } else { //this.offlineForItems(); } }; listenForItems(itemsRef) { this.itemsRef.on('value', (snap) => { const items = []; snap.forEach((child) => { items.unshift({ title: child.val().title, _key: child.key, }); }); offline2.save('itemsS', items); this.setState({ dataSource: this.state.dataSource.cloneWithRows(items), }); }); } offlineForItems() { offline2.get('itemsS').then((items) => { this.setState({ dataSource: this.state.dataSource.cloneWithRows(items), }); }); } deleteConfirm(data, secId, rowId, rowMap) { Alert.alert( 'Warning!', 'Are you sure?', [ { text: 'OK', onPress: () => this.deleteRow(data, secId, rowId, rowMap) }, { text: 'Cancel', onPress: () => this.deleteCancel(data, secId, rowId, rowMap) }, ] ); } deleteCancel(data, secId, rowId, rowMap) { rowMap[`${secId}${rowId}`].closeRow(); } deleteRow(data, secId, rowId, rowMap) { rowMap[`${secId}${rowId}`].closeRow(); this.itemsRef.child(data._key).remove(); offline2.get('itemsS').then((items) => { const itemsTemp = items; let index = -1; for (let i = 0; i < itemsTemp.length; i += 1) { if (itemsTemp[i]._key === data._key) { index = i; } } if (index > -1) { itemsTemp.splice(index, 1); } // Decrement stores counter offline2.get('storesTotal').then((value) => { const itemsReduce = value - 1; this.setState({ storesValue: itemsReduce }); offline2.save('storesTotal', itemsReduce); }); offline2.save('itemsS', itemsTemp); this.setState({ dataSource: this.state.dataSource.cloneWithRows(itemsTemp), }); }); }，您需要更改

bar

到

bar

Answer 2

$(function(){
  $( "#hit" ).click(function() {
    bar = +($('#num').text()) + 1;
    $("tr td:nth-child("+bar+")").toggleClass('on off');
  });
});

.on {
  background-color: green;
}

.off {
  background-color: grey;
}

table {
  border: 1px solid black;  
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>


<div id="num">1</div>
<br>
<table>
  <tr>
    <td class="on">&nbsp;</td>
    <td class="off">&nbsp;</td>
    <td class="off">&nbsp;</td>
    <td class="off">&nbsp;</td>
    <td class="off">&nbsp;</td>
  </tr>
</table>

<br>
<button id="hit">Hit me!</button>

我认为您想要切换on和off，您需要让两个课程都进行切换。也正确连接

Answer 3

你的功能有点偏。首先，你不是将bar作为变量引用，而是只包括字符串＆＃34; bar＆＃34;在选择器字符串中。其次，toggleClass（）很好，但你需要切换.on和.off，否则你的浏览器会尝试应用这两种样式（因为＆＃34; .off＆＃34;仍然是一类第n个孩子）。请参阅下面的代码：

＆＃13;

$(function(){
  $( "#hit" ).click(function() {
    bar = +($('#num').text()) + 1;
    $("tr td:nth-child(" + bar + ")").toggleClass('on off');
  });
});

＆＃13;

.on {
  background-color: green;
}

.off {
  background-color: grey;
}

table {
  border: 1px solid black;  
}

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>


<div id="num">1</div>
<br>
<table>
  <tr>
    <td class="on">&nbsp;</td>
    <td class="off">&nbsp;</td>
    <td class="off">&nbsp;</td>
    <td class="off">&nbsp;</td>
    <td class="off">&nbsp;</td>
  </tr>
</table>

<br>
<button id="hit">Hit me!</button>

＆＃13;

另外，以下是您可能想要做的其他事情： - 点击事件触发后更新$（＆＃39;＃num＆＃39;）的值 - 检查以确保存在第n个孩子

使用td：nth base从number更改类

3 个答案: