Question

我尝试返回ID为其中一个或多个Num_Occurrence行为＆gt; = 10的所有行。

以下是原始数据的示例：

+------+-----------+----------------+
| ID   | YearMonth | Num_Occurrence |
+------+-----------+----------------+
| 1234 | 201601    | 7              |
+------+-----------+----------------+
| 1234 | 201602    | 8              |
+------+-----------+----------------+
| 1234 | 201603    | 12             |
+------+-----------+----------------+
| 1234 | 201604    | 9              |
+------+-----------+----------------+
| 9898 | 201601    | 9              |
+------+-----------+----------------+
| 9898 | 201602    | 8              |
+------+-----------+----------------+
| 9898 | 201603    | 9              |
+------+-----------+----------------+
| 9898 | 201604    | 6              |
+------+-----------+----------------+

这是所需的输出：

+------+-----------+----------------+
| ID   | YearMonth | Num_Occurrence |
+------+-----------+----------------+
| 1234 | 201601    | 7              |
+------+-----------+----------------+
| 1234 | 201602    | 8              |
+------+-----------+----------------+
| 1234 | 201603    | 12             |
+------+-----------+----------------+
| 1234 | 201604    | 9              |
+------+-----------+----------------+

我知道以下内容不起作用：

SELECT *
FROM tbl
WHERE Num_Occurrence >= 10

因为那只会返回这一行：

+------+-----------+----------------+
| ID   | YearMonth | Num_Occurrence |
+------+-----------+----------------+
| 1234 | 201603    | 12             |
+------+-----------+----------------+

如前所述，我需要为NY_Occurrence> = 10的任何ID返回所有行。

谢谢！

Answer 1

SELECT * FROM [tbl] t1
WHERE EXISTS (SELECT * FROM [tbl] t2
              WHERE t2.ID = t1.id
              AND t2.Num_Occurrence >= 10);

＆＃34; EXISTS＆＃34;这里使用子句查询所有具有Num_Occurrence＆gt; = 10的行，然后将其与完整表进行比较，以获得具有匹配ID的所有行。

Answer 2

您可以这样做：

select t.*
from tbl t
where exists (select 1
              from tbl t2
              where t2.id = t.id and t2.id >= 10
             );

如何返回至少有一行符合条件的值的所有行？

2 个答案: