Question

我很难回答问题，并希望得到任何帮助：

声明名为bowl set的数组等于以下内容：

["jelly-bean", "m&m", "m&m", "chocolate", "m&m", "jelly-bean", "m&m", "m&m", "jelly-bean"]
接下来，声明三个变量：jbOccur，mOccur，chocOccur。将每个设置为0。
现在，声明一个名为occurrence的函数循环通过碗数组，并在步骤2中更改三个变量的值根据它们在碗阵中的相应出现次数。（提示：jbOccur变量在发生后应等于3 功能已经运行）。

到目前为止，这是我能够生产的，所以你知道我在哪里......：

var bowl = ["jelly-bean", "m&m", "m&m", "chocolate", "m&m", "jelly-bean", "m&m", "m&m", "jelly-bean"]

var jbOccur = 0
var mOccur = 0
var chocOccur = 0

var occurence = function (jbOccur, mOccur, choOccur){
  for (var i = 0; i < bowl.length; i++) {
    console.log(bowl[jbOccur, mOccur, chocOccur])
  }
};

Answer 1

试试这个：

var bowl = ["jelly-bean", "m&m", "m&m", "chocolate", "m&m", "jelly-bean", "m&m", "m&m", "jelly-bean"]

var stringOccur = function(stringArray, toFind){
  var occurance = 0;
  for (var elem in stringArray){
    if (stringArray[elem].indexOf(toFind) != -1){
      occurance++;
    }
  }
  return occurance;
}

var jbOccur = stringOccur(bowl, "jelly-bean");
var mOccur = stringOccur(bowl, "m&m");
var chocOccur = stringOccur(bowl, "chocolate");

console.log(jbOccur,mOccur,chocOccur);

js：循环遍历数组的函数

1 个答案: