我试图从URL中获取绘图,指向图像。但问题是,在android中你不应该在主线程上执行网络任务。因为它,我使用async / await块,但错误仍然一直发生。这是代码:
page.Appearing += async(sender, ev3) =>
{
if ( GetToolbar == null ) return;
GetToolbar.Subtitle = viewModel?.SubTitle;
if ( viewModel == null ) return;
if ( viewModel.AvatarUrl.Contains("?") && !viewModel.AvatarUrl.Contains("gravatar") )
viewModel.AvatarUrl = viewModel.AvatarUrl
.Substring(0, viewModel.AvatarUrl.IndexOf("?", StringComparison.Ordinal));
//var stream = Context.ContentResolver.OpenInputStream(Android.Net.Uri.Parse(viewModel.AvatarUrl));
await SetLogo(viewModel);
}
private async Task SetLogo(PublicRepositoryPageViewModel viewModel)
{
var url = new URL(viewModel.AvatarUrl);
var connection = url.OpenConnection();
var stream = connection.InputStream;
var logo = await Drawable.CreateFromStreamAsync(stream, viewModel.Title + "_avatar");
GetToolbar.Logo = logo;
}
确切地说,它出现在这一行:
var stream = connection.InputStream;
如果我使用OpenInputStream而不是它,那么它会抛出 Java.IO.FileNotFoundException:没有内容提供者:https://avatars.githubusercontent.com/u/6516107
我已检查过互联网许可。
这是Xamarin.Forms Android项目
解答:
await Task.Run(async() => {
var url = new URL(viewModel.AvatarUrl);
var connection = url.OpenConnection();
var stream = connection.InputStream;
var logo = await Drawable.CreateFromStreamAsync(stream, viewModel.Title + "_avatar");
Device.BeginInvokeOnMainThread(()=>GetToolbar.Logo = logo);
});
答案 0 :(得分:3)
Task.Run
会让你离开主线程并进入默认Threadpool中的一个线程:
await Task.Run(async() => {
var url = new URL(viewModel.AvatarUrl);
var connection = url.OpenConnection();
var stream = connection.InputStream;
var logo = await Drawable.CreateFromStreamAsync(stream, viewModel.Title + "_avatar");
GetToolbar.Logo = logo;
});