Question

有两个表Group和User。 users可以同时属于多个群组。

组

class Group(db.Model):
       """ Group model """
       __tablename__ = "group"
       id = db.Column(db.Integer, primary_key=True)
       project_id = db.Column(db.Integer, db.ForeignKey("project.id"), nullable=True)
       project = db.relationship("Project", foreign_keys=[project_id])
       active = db.Column(db.Boolean, default=True, index=True)
       name = db.Column(db.String(64), index=True)

用户

class User(db.Model, UserMixin):
    """ User model """
    __tablename__ = "user"

    id = db.Column(db.Integer, primary_key=True)   
    email = db.Column(db.String(128), unique=True, index=True)
    email_confirmed = db.Column(db.Boolean, default=False)    
    password = db.Column(db.String(256), nullable=True)
    groups = db.relationship("Group", secondary=user_has_group, lazy="dynamic",
                     backref=db.backref("users", lazy="dynamic"))

必须为每组用户显示代码。

groups = Group.query.all()
for group in groups:
    users = User.query.filter(group in User.groups).all()

但代码未运行。

请帮助我了解每个users的{{1}}。

Answer 1

您的User有back reference backref=db.backref("users", lazy="dynamic")

因此，从Group对象，您可以使用group.users来获取给定组中的用户，例如

groups = Group.query.all()
for group in groups:
    users = group.users

按关系过滤sqlalchemy Python

1 个答案: