我的程序是一个秒表，基本上，当你点击public partial class Invoices : System.Web.UI.Page
{
MySql.Data.MySqlClient.MySqlConnection conn ;
MySql.Data.MySqlClient.MySqlCommand cmd;
String querystr;
protected void Page_Load(object sender, EventArgs e)
{
}
protected void Button1_Click(object sender, EventArgs e)
{
if (FileUpload1.HasFile)
{
//save image into database
string str = FileUpload1.FileName;
FileUpload1.PostedFile.SaveAs(Server.MapPath(".") + "//Invoices//" + str);
string path = "~//Invoices//" + str.ToString();
MySqlConnection conn = new MySqlConnection("Server=127.0.0.1;Database=admindb;Uid=root;Pwd=8888;");
MySqlCommand cmd = new MySqlCommand("insert into invoicesfp values (@v1)", conn);
conn.Open();
cmd.Parameters.AddWithValue("v1", TextBox1.Text);
cmd.ExecuteNonQuery();
conn.Close();
Label4.Text = "Image uploaded sucessfully";
}
else
{
Label4.Text = " Please, upload the image ";
}
}
}
时，它应该在它停止时停止。但是，我不知道如何在不重置时钟的情况下做到这一点。此外，如果我在stopImage按钮外单击两次，时钟开始，如果我然后单击startImage，它将重置为零。我正在使用的图形包是Zelle's graphics。
stopImage