Question

我有3个json文件：

sources.json
destination_level1.json
destination_level0.json（最终文件）

我想通过替换匹配的字符串来“合并”所有这些文件，例如

destination_level0 - ＆gt; destination_level1 - ＆gt;来源

单词：“检查destination_level0中的键，例如”Element1“，转到destination_level1并查找匹配的对象，并将destination_level0中的Element1替换为该对象。”从destination_level1到源也是如此。

来源可能如下所示：

{"john": ["A","B"],"mike": ["123","234","345"],"doe": ["abc","cde"],"ann": {"abc": ["yxc","xcv","cvb"],"bcd": ["poi","iuz","uzt"]}}

destination_level_1是这样的：

{"Element1": ["john","ann","john","john","doe","mike"],"Element2": ["ann","mike","ann","doe","doe","doe","ann"],"Element3": ["ann","doe","ann"]}

和destination_level_0是这样的：

{"FinalA": ["Element1","Element2","Element1","Element2","Element2"],"FinalB": ["Element2","Element2","Element2","Element1"]}

最终结果应如下所示：

{"FinalA": [[["A","B"],{"abc": ["yxc","xcv","cvb"],"bcd": ["poi","iuz","uzt"]},...

我尝试了一些lodash＆amp;强调，但卡住了。

有什么想法吗？

Answer 1

仅使用纯JavaScript

var sources = {"john": ["A","B"],"mike": ["123","234","345"],"doe": ["abc","cde"],"ann": {"abc": ["yxc","xcv","cvb"],"bcd": ["poi","iuz","uzt"]}};
    var destination_level_0 = {"FinalA": ["Element1","Element2","Element1","Element2","Element2"],"FinalB": ["Element2","Element2","Element2","Element1"]};
    var destination_level_1 = {"Element1": ["john","ann","john","john","doe","mike"],"Element2": ["ann","mike","ann","doe","doe","doe","ann"],"Element3": ["ann","doe","ann"]};
    
    var final = {};
    for(var key in destination_level_0){
        var preFinal = [];
        var elems = destination_level_0[key];
        for(var i in elems){
            var elem = elems[i];
            var names = destination_level_1[elem];
            for(var j in names){
                var name = names[j];
                var finalItem = sources[name];
                preFinal.push(finalItem); 
            }
        }
        final[key] = preFinal;
    }
    
    console.log(final);
    console.log(JSON.stringify(final));

Answer 2

映射level0 =＆gt;中的项目level1 =＆gt;在Array#map（或lodash的Array#.map）内使用_.map()的level2：

var level0 = {"FinalA": ["Element1","Element2","Element1","Element2","Element2"],"FinalB": ["Element2","Element2","Element2","Element1"]};
var level1 = {"Element1": ["john","ann","john","john","doe","mike"],"Element2": ["ann","mike","ann","doe","doe","doe","ann"],"Element3": ["ann","doe","ann"]};
var level2 = {"john": ["A","B"],"mike": ["123","234","345"],"doe": ["abc","cde"],"ann": {"abc": ["yxc","xcv","cvb"],"bcd": ["poi","iuz","uzt"]}}
;

var result = Object.keys(level0).reduce(function(r, key) {
  r[key] = level0[key].map(function(element) {
    return level1[element].map(function(item) {
      return level2[item];
    });
  }) 
  
  return r;
}, Object.create(null));

console.log(JSON.stringify(result));

用其他json文件中的对象替换字符串

2 个答案: