Question

我是一个新的python程序员，目前正在开发一个非常简单的python转换器。我目前有这个，但我想这样做＆＃39; n＆＃39;可以随时更改。

#inches to centimeters
def in_inches(n):
    resulti = n * 100
    return resulti

n = 10
resulti = in_inches(n)
print "In %d inches we have %d centimeters" % (n, resulti)

#pounds to kilograms
def in_pounds(x):
    resultp = x * 0.453592
    return resultp

x = 10.0
resultp = in_pounds(x)
print "In %d pounds we have %d kilograms." % (x, resultp)

Answer 1

您可以按照评论中的说明获取值raw_input()（Py3的input()），也可以将它们作为脚本的args。这是一个小例子，只收集所有-i args表示in_inches()，所有-p参数表示in_pounds()：

from __future__ import print_function   # Really should start moving to Py3

#inches to centimeters
def in_inches(n):
    resulti = n * 2.56
    return resulti

#pounds to kilograms
def in_pounds(x):
    resultp = x * 0.453592
    return resultp

if __name__ == '__main__':
    from argparse import ArgumentParser
    parser = ArgumentParser()
    parser.add_argument('-i', '--inches', default=[], type=float, action='append')
    parser.add_argument('-p', '--pounds', default=[], type=float, action='append')
    args = parser.parse_args()

    for n in args.inches:
        print("In {} inches we have {} centimeters".format(n, in_inches(n)))
    for x in args.pounds:
        print("In {} inches we have {} centimeters".format(x, in_pounds(x)))

然后你只需用你想要的任何参数调用脚本：

$ python myconverter.py -p 7 -i 42 -p 10 -p 12
In 42.0 inches we have 107.52 centimeters
In 7.0 pounds we have 3.175144 kilos
In 10.0 pounds we have 4.53592 kilos
In 12.0 pounds we have 5.443104 kilos

Answer 2

def in_to_cen(num):
    return(num * 2.54)
def pds_to_kg(num):
    return(num *0.453592)
while True:
    print "which conversion?"
    print "'1' = pounds to kilograms"
    print "'2' = inches to centimeters"
    choice = raw_input("? ")
    if choice == "1":
        num = input("how many pounds? ")
        res = pds_to_kg(num)
        print str(num) + " is " + str(res) + " Kilograms"
    elif choice == "2":
        num = input("how many inches? ")
        print str(num) + " is " + str(res) + " centimeters."
    else:
        print "invalid choice"

这就是我认为你想要的。

此程序有一个菜单，询问要进行的转换，然后根据该选项从用户获取数字输入，然后输出正确的转换。

Answer 3

您可以创建单个函数并在其中执行所有转换，而不是创建许多函数：

def convert(n, fromto):
    if fromto == "in_cm":
        print "In %d inches we have %d centimeters" %(n, n*100)
    if fromto == "kg_pound":
        print "In %d pounds we have %d kilograms." %(n, n*0.453592)

convert(2, "in_cm")
convert(5, "kg_pound")

输出：

In 2 inches we have 200 centimeters
In 5 pounds we have 2 kilograms.

Python简单转换器

3 个答案: