Question

我运行此代码但我的编译器不想运行它并在第47行给我错误 infile.open（fileloc，IOS ::在）;

有什么建议吗？谢谢

#include<iostream>
#include<iomanip>
#include<sstream>
#include<fstream>

using namespace std;

void encrypt(); // encrypt function protype
void decrypt();

int main()
{
    int choice;
    bool done = false;

    while(!done){
        cout << "What you want to do?\n1) Encrypt a file.\n2) Decrypt a file." << endl;
        cin >> choice;

        if (choice == '1')
        {
            encrypt();
            done = true;
        }
        if (choice == '2')
        {   decrypt();
            done = true;
        }
        else
        {   cout <<"Invalid input try again"<<endl;
        }
    }

}

void encrypt()
{
    string outfile;
    string fileloc;
    string x;
    char y;
    fstream infile;
    fstream outputFile;

    cout << "What is the name of the file you want to encrypt? " << endl;
    cin >> fileloc;
    infile.open(fileloc,ios::in);

    while(!infile){
    cout << "Your file does not exist, enter a valid file name..."<< endl;
    cin >> fileloc;
    infile.open(fileloc,ios::in);
    }
    cout << "What is the name of your output file?" << endl;
    cin >> outfile;
    outputFile.open(outfile,ios::out);
    while(infile>>noskipws>>y){
        outputFile << char(y+10);
    }
}

void decrypt()
{
        string outfile;
        string fileloc;
        char y;
        fstream infile;
        fstream outputFile;

        cout << "What is the name of the file you want to decrypt? " << endl;
        cin >> fileloc;
        infile.open(fileloc,ios::in);

        while(!infile){
        cout << "Your file does not exist, enter a valid file name..."<< endl;
        cin >> fileloc;
        infile.open(fileloc,ios::in);
        }
        cout << "What is the name of your output file?" << endl;
        cin >> outfile;
        outputFile.open(outfile,ios::out);
        while(infile>>noskipws>>y){
                outputFile << char(y-10);
    }
}

该程序应通过向文件中的每个ASCII字符添加10来进行基本加密。

Answer 1

infile.open(fileloc, ios::in)

这并不适用于所有标准。如果您正在使用C ++ 11，那很好。但是，许多编译器默认使用较旧的标准。您可以尝试使用

infile.open(fileloc.c_str(), ios::in)

这将获取std::string的c-string表示形式，该代码与fstream::open兼容。

如果看一下here，您会发现C ++过去只允许const char *作为路径的参数。

您还可以确保您当然使用兼容的标准，支持const std::string&作为路径的参数类型。

fstream对象出错

1 个答案: