使用价格范围值填充数据库

时间：2016-12-11 00:36:26

标签： sql-server data-modeling

我坚持尝试填充具有价格范围的给定表格。我已经尝试了十进制数据类型，数字，浮点数，但没有任何对我有用。 更具体地说，我不太了解如何为＆＃34;订单金额编写脚本＆＃34;列，因为它具有价格范围内的值。

表：enter image description here

和我尝试的脚本.. 

  DROP TABLE MAIL_ORDERS;
CREATE TABLE MAIL_ORDERS (
amountofOrder MONEY not null PRIMARY KEY,
orderID INT not null);

DROP TABLE DELIVERY_DETAILS;
CREATE TABLE DELIVERY_DETAILS (
deliveryID INT not null PRIMARY KEY,
regular MONEY not null,
rush MONEY not null,
express MONEY not null,
amountofOrder MONEY not null,
CONSTRAINT fk_deliverydetails_mailorders FOREIGN KEY (amountofOrder)
REFERENCES MAIL_ORDERS (amountofOrder));

INSERT INTO MAIL_ORDERS (amountofOrder, orderID) VALUES ($0.00 - $15.00, 1);
INSERT INTO MAIL_ORDERS (amountofOrder, orderID) VALUES ($15.01 - $30.00, 2);
INSERT INTO MAIL_ORDERS (amountofOrder, orderID) VALUES ($30.01 - $45.00, 3);
INSERT INTO MAIL_ORDERS (amountofOrder, orderID) VALUES ($45.01 - $65.00, 4);
INSERT INTO MAIL_ORDERS (amountofOrder, orderID) VALUES ($65.01 - $90.00, 5);
INSERT INTO MAIL_ORDERS (amountofOrder, orderID) VALUES ($90.01 - $125.00, 6);
INSERT INTO MAIL_ORDERS (amountofOrder, orderID) VALUES ($125.01 - $200.00, 7);
INSERT INTO MAIL_ORDERS (amountofOrder, orderID) VALUES ($200.01 - null, 8);

INSERT INTO DELIVERY_DETAILS (deliveryID, regular, rush, express, amountofOrder)
VALUES (1, $4.95, $9.95, $17.45, $0.00 - $15.00);
INSERT INTO DELIVERY_DETAILS (deliveryID, regular, rush, express, amountofOrder)
VALUES (2, $5.95, $10.95, $18.45, $15.01 - $30.00);
INSERT INTO DELIVERY_DETAILS (deliveryID, regular, rush, express, amountofOrder)
VALUES (3, $7.95, $12.95, $20.45, $30.01 - $45.00);
INSERT INTO DELIVERY_DETAILS (deliveryID, regular, rush, express, amountofOrder)
VALUES (4, $9.95, $14.95, $22.45, $45.01 - $65.00);
INSERT INTO DELIVERY_DETAILS (deliveryID, regular, rush, express, amountofOrder)
VALUES (5, $11.95, $16.95, $24.45, $65.01 - $90.00);
INSERT INTO DELIVERY_DETAILS (deliveryID, regular, rush, express, amountofOrder)
VALUES (6, $13.95, $18.95, $26.45, $90.01 - $125.00);
INSERT INTO DELIVERY_DETAILS (deliveryID, regular, rush, express, amountofOrder)
VALUES (7, $14.95, $19.95, $27.45, $125.01 - $200.00);
INSERT INTO DELIVERY_DETAILS (deliveryID, regular, rush, express, amountofOrder)
VALUES (8, $16.95, $21.95, $29.45, $200.01 - null);

SELECT * FROM MAIL_ORDER
SELECT * FROM DELIVERY_DETAILS

3 个答案:

答案 0 :(得分：1)

好的......好吧

INSERT INTO MAIL_ORDERS (amountofOrder, orderID) VALUES ($15.01 - $30.00, 2); 
--Cristina:  Actually you are substracting $15.01 - $30.00 = -14.99

你不能那样做，你需要两个领域，这种关系不太好。

通常我们将int设置为主键。

检查示例：

DROP TABLE MAIL_ORDERS;
create TABLE MAIL_ORDERS (
amountofOrderInit MONEY not null,
amountofOrderEnd MONEY null,
orderID INT not null primary key);

      go

DROP TABLE DELIVERY_DETAILS;
CREATE TABLE DELIVERY_DETAILS (
deliveryID INT not null PRIMARY KEY,
regular MONEY not null,
rush MONEY not null,
express MONEY not null,
orderID int not null,
CONSTRAINT fk_deliverydetails_mailorders FOREIGN KEY (orderID)
REFERENCES MAIL_ORDERS (orderID));

go

INSERT INTO MAIL_ORDERS (amountofOrderInit, amountofOrderEnd, orderID) VALUES ($0.00 , $15.00, 1);
INSERT INTO MAIL_ORDERS (amountofOrderInit, amountofOrderEnd, orderID) VALUES ($15.01 , $30.00, 2); --Cristina:  Actually you are substracting $15.01 - $30.00 = -14.99
INSERT INTO MAIL_ORDERS (amountofOrderInit, amountofOrderEnd, orderID) VALUES ($30.01 , $45.00, 3); 
INSERT INTO MAIL_ORDERS (amountofOrderInit, amountofOrderEnd, orderID) VALUES ($45.01 , $65.00, 4);
INSERT INTO MAIL_ORDERS (amountofOrderInit, amountofOrderEnd, orderID) VALUES ($65.01 , $90.00, 5);
INSERT INTO MAIL_ORDERS (amountofOrderInit, amountofOrderEnd, orderID) VALUES ($90.01 , $125.00, 6);
INSERT INTO MAIL_ORDERS (amountofOrderInit, amountofOrderEnd, orderID) VALUES ($125.01 , $200.00, 7);
INSERT INTO MAIL_ORDERS (amountofOrderInit, amountofOrderEnd, orderID) VALUES ($200.01 , null, 8);

INSERT INTO DELIVERY_DETAILS (deliveryID, regular, rush, express, orderID)
VALUES (1, $4.95, $9.95, $17.45, 1);
INSERT INTO DELIVERY_DETAILS (deliveryID, regular, rush, express, orderID)
VALUES (2, $5.95, $10.95, $18.45, 2);
INSERT INTO DELIVERY_DETAILS (deliveryID, regular, rush, express, orderID)
VALUES (3, $7.95, $12.95, $20.45, 3);
INSERT INTO DELIVERY_DETAILS (deliveryID, regular, rush, express, orderID)
VALUES (4, $9.95, $14.95, $22.45,4);
INSERT INTO DELIVERY_DETAILS (deliveryID, regular, rush, express, orderID)
VALUES (5, $11.95, $16.95, $24.45, 5);
INSERT INTO DELIVERY_DETAILS (deliveryID, regular, rush, express, orderID)
VALUES (6, $13.95, $18.95, $26.45, 6);
INSERT INTO DELIVERY_DETAILS (deliveryID, regular, rush, express, orderID)
VALUES (7, $14.95, $19.95, $27.45, 7);
INSERT INTO DELIVERY_DETAILS (deliveryID, regular, rush, express, orderID)
VALUES (8, $16.95, $21.95, $29.45, 8);


SELECT 
    mo.*
    ,cONCAT('$ ', mo.amountofOrderInit, ' - ' ,'$ ',mo.amountofOrderEnd) as amountofOrder --add column only for the query
FROM MAIL_ORDERS mo

SELECT 
    dd.* 
,CONCAT('$ ', mo.amountofOrderInit, ' - ' ,'$ ', mo.amountofOrderEnd) as amountofOrder --add column only for the query, in this case the info comes from the MAIL_ORDERS table
FROM DELIVERY_DETAILS dd     
    inner join MAIL_ORDERS mo     --Add a relationship between the tables
    on  dd.orderID = mo.orderID

那么......你想用这些数据做什么？

我将只使用一个表，例如：

declare @priceByAmount table(
    id int identity not null primary key ,
    initialAmount money not null,
    finalAmount money,
    reguarDelivery money not null,
    rushDelivery money not null,
    expressDelivery money not null
);

insert into @priceByAmount values (0,15,4.95,9.95,17.45)
insert into @priceByAmount values (15.01,30,5.95, 10.95, 18.45)
insert into @priceByAmount values (30.01,45, 7.95, 12.95, 20.45)
insert into @priceByAmount values (45.01,65,9.95, 14.95, 22.45)
insert into @priceByAmount values (65.01,90,11.95, 16.95, 24.45)
insert into @priceByAmount values (90.01,125,13.95, 18.95, 26.45)
insert into @priceByAmount values (125.01,200,14.95, 19.95, 27.45)
insert into @priceByAmount values (200.01,null,16.95, 21.95, 29.45)


select 
    --*
    CONCAT('$ ', initialAmount,  isnull(' to $' + convert(nvarchar(100),finalAmount),' + ')) as [Amount of Order]
    ,reguarDelivery [Regular Delivery 7-10 Days]
    ,rushDelivery [Rush Delivery 4-5 Business Days]
    ,expressDelivery [Express Delivery 1-2 Business Days]
from @priceByAmount

答案 1 :(得分：0)

我肯定会为这样的东西推荐3张桌子，这样如果你需要更改运送选项，日期范围，个别价格，扩展以依赖于另一张桌子，它将灵活变换而无需做大事代码重构。

无论如何，我会把它标准化为：

CREATE TABLE AmountRanges (
    AmountRangeId INT NOT NULL AUTO_INCREMENT PRIMARY KEY
    ,StartRange NUMERIC(15,4) NOT NULL
    ,EndRange NUMERIC(15,4) NOT NULL
);

CREATE TABLE ShippingOptions (
    ShippingOptionId INT NOT NULL AUTO_INCREMENT PRIMARY KEY
    ,StartRange INT NOT NULL
    ,EndRange INT NOT NULL
    ,Description VARCHAR(50)
); 

CREATE TABLE ShippingPrices (
    ShippingPriceId INT NOT NULL AUTO_INCREMENT PRIMARY KEY
    ,AmountRangeId INT NOT NULL
    ,ShippingOptionId INT NOT NULL
    ,Price NUMERIC(15,4) NOT NULL
    ,FOREIGN KEY (AmountRangeId) REFERENCES AmountRanges (AmountRangeId)
    ,FOREIGN KEY (ShippingOptionId) REFERENCES ShippingOptions (ShippingOptionId)
);


INSERT INTO AmountRanges (StartRange, EndRange) VALUES (0,15),(15.01,30),(30.01,45),(45.01,65),(65.01,90);
INSERT INTO ShippingOptions (StartRange, EndRange,Description) VALUES (7,10,'Regular Delivery 7-10 days')
,(4,5,'Rush Delivery 4-5 Busienss Days'),(1,2,'Express Delivery 1-2 Business Days');
INSERT INTO ShippingPrices (AmountRangeId,ShippingOptionId,Price) VALUES (1,1,4.95),(1,2,9.95),(1,3,17.45)
,(2,1,5.95),(2,2,10.95),(2,3,18.45),(3,1,7.95),(3,2,12.95),(3,3,20.45)
,(4,1,9.95),(4,2,14.95),(4,3,22.45),(5,1,11.95),(5,2,16.95),(5,3,24.45);


SELECT
    p.ShippingPriceId
    ,a.StartRange as AmountStartRange
    ,a.EndRange as AmountEndRange
    ,o.StartRange as DaysStartRange
    ,o.EndRange as DaysEndRange
    ,o.Description
    ,p.Price
FROM
   ShippingPrices p
   INNER JOIN AmountRanges a
   ON p.AmountRangeId = a.AmountRangeId
   INNER JOIN ShippingOptions o
   ON p.ShippingOptionId = o.ShippingOptionId
;

这是一个显示其工作原理的链接http://rextester.com/l/mysql_online_compiler

如果您真的希望表格格式完全相同，那么您所要做的就是转移出货选项。在这种情况下，我建议使用条件聚合来进行转移。

答案 2 :(得分：0)

如果数据值是一个范围，我认为你用两列设计它们会更好地进行处理，例如，你可以改变表MAIL_ORDERS如下，当进程数据如查询使用start dan end value时，新的cloumn AmountofOrder是显示和主键的计算cloumn。

CREATE TABLE MAIL_ORDERS (
    AmountofOrderStart MONEY,
    AmountofOrderEnd MONEY,
    AmountofOrder AS ISNULL('$'+LTRIM(AmountofOrderStart),'Lesst than ')+ISNULL(' - $'+LTRIM(AmountofOrderEnd), ' +'),
    orderID INT not NULL,
    CONSTRAINT [PK_MAIL_ORDERS] PRIMARY KEY CLUSTERED (AmountofOrder)
)
INSERT INTO MAIL_ORDERS(AmountofOrderStart,AmountofOrderEnd, orderID) VALUES ($0.00, $15.00, 1);
INSERT INTO MAIL_ORDERS (AmountofOrderStart,AmountofOrderEnd, orderID) VALUES ($15.01 , $30.00, 2);
INSERT INTO MAIL_ORDERS (AmountofOrderStart,AmountofOrderEnd, orderID) VALUES ($30.01 , $45.00, 3);
INSERT INTO MAIL_ORDERS (AmountofOrderStart,AmountofOrderEnd, orderID) VALUES ($45.01 , $65.00, 4);
INSERT INTO MAIL_ORDERS (AmountofOrderStart,AmountofOrderEnd, orderID) VALUES ($65.01 , $90.00, 5);
INSERT INTO MAIL_ORDERS (AmountofOrderStart,AmountofOrderEnd, orderID) VALUES ($90.01 , $125.00, 6);
INSERT INTO MAIL_ORDERS (AmountofOrderStart,AmountofOrderEnd, orderID) VALUES ($125.01 , $200.00, 7);
INSERT INTO MAIL_ORDERS (AmountofOrderStart,AmountofOrderEnd, orderID) VALUES ($200.01 , null, 8);

SELECT * FROM MAIL_ORDERS ORDER BY AmountofOrderStart

AmountofOrderStart    AmountofOrderEnd      AmountofOrder                                                                         orderID
--------------------- --------------------- ------------------------------------------------------------------------------------- -----------
0.00                  15.00                 $0.00 - $15.00                                                                        1
15.01                 30.00                 $15.01 - $30.00                                                                       2
30.01                 45.00                 $30.01 - $45.00                                                                       3
45.01                 65.00                 $45.01 - $65.00                                                                       4
65.01                 90.00                 $65.01 - $90.00                                                                       5
90.01                 125.00                $90.01 - $125.00                                                                      6
125.01                200.00                $125.01 - $200.00                                                                     7
200.01                NULL                  $200.01+                                                                              8
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