Question

我有一个文本文件，其中包含四行的任意（非Python）列表，如下所示：

WHAT
EVER
0.00000904
17577

FOO
BAR
7.00000031
426

该文件包含数千个这样的块。如何将文件中的数据转换为列表字典，其中键是每个块的前两行，连接，接下来的两行是列表值？例如：

{'WHATEVER': [0.00000904, 17577], 'FOOBAR': [7.00000031, 426]}

Answer 1

尝试以下方法：

import re

# Open the file
data = open('odd_lines.txt').read()

# Split on the double newline characters
data = data.split("\n\n")

# Split each element of the data list on the newline characters followed by a float
data = [re.split("\n(\d+\.\d+)", x) for x in data]

# Put the data in a dictionary with the key being the first element of each element of the data list.
# Make sure to replace the newline character with an empty space
output = {x[0].replace("\n",""):[float(y) for y in x[1:]] for x in data}

print(output)

这应该产生：

#{'FOOBAR': [7.00000031, 426], 'WHATEVER': [0.00000904, 17577]}

以下是起始文件（odd_lines.txt）：

WHAT
EVER
0.00000904
17577

FOO
BAR
7.00000031
426

我希望这会有所帮助。

Answer 2

您可以执行以下操作：

import os

# set base path to main dir of target file
root = os.getcwd()
# split on double spaces
vals = open(os.path.join(root, 'test.txt'), 'r').read().split('\n\n')

# create empty dictionary to store values
valdict = {}

# iterate over each item which should contain the keys and values
for val in vals:
    # fill in dict with key and turn numbers into float and dict value as float list
    key = ''.join(val.split('\n')[0:2])
    nums = val.split('\n')[2:]
    nums = map(float, nums)
    valdict[key] = nums

valdict
# output: {'FOOBAR': [7.00000031, 426.0], 'WHATEVER': [9.04e-06, 17577.0]}

Python：将文本文件的行转换并连接到具有列表值的字典中

2 个答案: