Question

在我的代码中，我有一个具有两个或六个属性的对象，我需要知道是否存在特定的值组合：

var myObject = {
  name: "John Smith",
  type = "person"
  prop1: "",
  prop2: "",
  prop3: "",
  prop4: ""
};

或

var myObject = {
  name: "My Business Name",
  type = "business"
};

我需要确定对象是否具有以下两个条件之一：

name的值为＆＃34; business＆＃34;
name有一个值，类型是＆＃34; person＆＃34;而其他四个属性没有价值。

如果它符合这两个条件中的一个，我把它放在一个地方，否则我把它放在另一个地方。如上所示，if type == "business，prop1-prop4不存在于对象中，但是if type == "person"，它们确实存在。

在不必每次都专门检查prop1 - prop 4的情况下，有什么简单的方法可以做到这一点？

我正在查看lodash函数，看看是否有一个（或更多链接在一起）可以做到这一点，但我还没有确定一个。我也对纯JS选项持开放态度。

感谢。

Answer 1

最简单的方法是以下方法（事实上，它使用的是vanilla JavaScript！）：

var myObject1 = {
  name: "John Smith",
  type: "person",
  prop1: "",
  prop2: "",
  prop3: "",
  prop4: ""
};

var myObject2 = {
  name: "My Business Name",
  type: "business"
};

doStuff(myObject1);
doStuff(myObject2);

function doStuff(obj) {
  var properties = Object.keys(obj);

  switch (obj.type) {
    case "person":
      if (["name", "prop1", "prop2", "prop3", "prop4"].every(p => properties.includes(p))) {
        // Do stuff with a valid person 
        console.log("This person is fine!");
      }
      break;

    case "business":
      if (properties.includes("name")) {
        // Do stuff with a valid business
        console.log("This business is fine!");
      }
      break;
  }
}

Answer 2

Checking for those conditions inside a function is one solution.   
var myObject = {
 name: "John Smith",
 type = "person"
 prop1: "",
 prop2: "",
 prop3: "",
 prop4: ""
};    
var validated = validateObject(myObject);
 function validateObject(obj){

   if((obj[name] &&  obj[type] === "business") || ((obj[name] &&  obj[type] === "person" && !obj[prop1] && !obj[prop2] && !obj[prop3] && !obj[prop4])) ){
    return true;
 }
 return false;
}

Answer 3

您可以使用函数和单个if条件

＆＃13;

var myObject = {
  name: "John Smith",
  type : "person",
  prop1: "",
  prop2: "",
  prop3: "",
  prop4: ""
};

var myObject1 = {
  name: "My Business Name",
  type: "business"
};

let checkProps = (obj, objName) => {
  let {name, type, prop1, prop2, prop3, prop4} = obj, len = name.length;
  if (len && type === "busines" || len && type === "person" 
      && prop1 + prop2 + prop3 + prop4 === "") {
    console.log(objName + " meets one of two conditions")
  } else {
    console.log(objName + " does not meet one of two conditions")
  }
}

checkProps(myObject, "myObject");

checkProps(myObject1, "myObject1");

＆＃13;

快速查看对象是否只具有值的特定属性的方法

3 个答案: