Question

我有一个JSON字符串，我正在尝试反序列化到以下类的列表中：

public class Selection
{
    public Int64 id { get; set; }
    public bool view { get; set; }
    public bool edit { get; set; }
    public bool broad { get; set; }
}

这是我得到的JSON字符串：

[
    [
        {"name":"id", "value":0},
        {"name":"view", "value":true},
        {"name":"edit", "value":false},
        {"name":"broad", "value":false}
    ],
    [
        {"name":"id", "value":0},
        {"name":"view", "value":false},
        {"name":"edit", "value":false},
        {"name":"broad", "value":false}
    ],
    [
        {"name":"id", "value":0},
        {"name":"view", "value":true},
        {"name":"edit", "value":false},
        {"name":"broad", "value":false}
    ],
    [
        {"name":"id", "value":0},
        {"name":"view", "value":true},
        {"name":"edit", "value":false},
        {"name":"broad", "value":false}
    ],
    [
        {"name":"id", "value":0},
        {"name":"view", "value":false},
        {"name":"edit", "value":false},
        {"name":"broad", "value":false}
    ],
    [
        {"name":"id", "value":0},
        {"name":"view", "value":false},
        {"name":"edit", "value":false},
        {"name":"broad", "value":false}
    ],
    [
        {"name":"id", "value":0},
        {"name":"view", "value":false},
        {"name":"edit", "value":false},
        {"name":"broad", "value":false}
    ],
    [
        {"name":"id", "value":0},
        {"name":"view", "value":false},
        {"name":"edit", "value":false},
        {"name":"broad", "value":false}
    ],
    [
        {"name":"id", "value":0},
        {"name":"view", "value":false},
        {"name":"edit", "value":false},
        {"name":"broad", "value":false}
    ],
    [
        {"name":"id", "value":0},
        {"name":"view", "value":false},
        {"name":"edit", "value":false},
        {"name":"broad", "value":false}
    ]
]

这就是我所谓的反序列化：

 var selection = JsonConvert.DeserializeObject<List<Selection>>(param.selection);

但是我收到了这个错误：

我需要其他类型的格式吗？

Answer 1

这个JSON不会轻易解析，你在JSON中将params的名称作为字典的值。这样做的最好方法是将JSON更改为：

[
{
        id :12345,
        view:true,
        edit : true,
        broad :true
},
.....
]

就像这样，它将使用相同的代码进行解析。

如果您无法更改JSON，那么您的代码必须使用反射来设置属性。或者解析为Dictionary并在其上循环，对于每个属性，将其值设置为新对象。

Answer 2

您收到此错误是因为JSON的形状与您尝试反序列化的结构不匹配。您的JSON表示一组名称 - 值对对象的数组，但您尝试反序列化为List<Selection>。要反序列化到您定义的类中，您需要使用这样的自定义JsonConverter：

public class SelectionConverter : JsonConverter
{
    public override bool CanConvert(Type objectType)
    {
        return objectType == typeof(Selection);
    }

    public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
    {
        var obj = new JObject(
            JArray.Load(reader)
                  .Children<JObject>()
                  .Select(jo => new JProperty((string)jo["name"], jo["value"]))
            );
        var selection = new Selection();
        serializer.Populate(obj.CreateReader(), selection);
        return selection;
    }

    public override bool CanWrite
    {
        get { return false; }
    }

    public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
    {
        throw new NotImplementedException();
    }
}

然后，你可以像这样反序列化：

var selection = JsonConvert.DeserializeObject<List<Selection>>(param.selection, new SelectionConverter());

小提琴：https://dotnetfiddle.net/pgAvUA

Answer 3

请找到以下解释来序列化j子串。在我的例子中，我有一个包含学生详细信息的字符串，如下所示。

  string json = @"{""data"":[{""id"":""1"",""name"":""A""}, {""id"":""2"",""name"":""B""}, {""id"":""3"",""name"":""C""}, {""id"":""5"",""name"":""D""}]}";

我使用下面的类结构。

   public class Students
   {
       public List<StudentDetails> data { get; set; }
   }
   public class StudentDetails
   {
       public string id { get; set; }
       public string name { get; set; }



   }

使用下面的代码行来序列化json字符串

 Students studentdetails = new JavaScriptSerializer().Deserialize<Students>(json);

这里的JavaScriptSerializer（）类存在于system.Web.Extensions程序集中。如果这有帮助，请将此标记为答案。

如何将名称 - 值对数组的JSON数组反序列化为List <myclass>

3 个答案: