这个程序在我的实践中是一个非常简单的代码来学习C ++。问题是在某些时候它不接受来自cin
的输入并且行为奇怪。
程序的代码和输出如下。
为什么程序不考虑cin
请“输入您的名字”?
# include "cmath"
# include <iostream>
using namespace std;
int main()
{
string FirstName, MiddleName, LastName;
string WelcomeMessage = "Welcome to Visual C++";
int Number_of_Steps = 5;
int LoopStart = 1, LoopEnd = 5;
int AgeYears, AgeMonths;
double Pi = 3.14;
float k = 5.366;
double Age;
char* Symbol = "k";
bool TestResult = true;
MiddleName = "Milton";
cout << "Input Your First Name and Last Name" << endl;
cin >> FirstName >> LastName;
cout << "Input your Age in Years" << endl;
cin >> AgeYears;
cout << "Imput your Age in Months " << endl;
cin >> AgeMonths;
Age = AgeYears + AgeMonths / 12;
cout << endl << "Your Name is " << FirstName << ' ' << LastName << endl;
cout << "Your Age is " << Age << endl;
cout << "The Character is " << Symbol << endl;
// Testing operators
cout << "Please Enter a floating point number \n";
int n;
cin >> n;
cout << "n==" << n
<< "\n n+1==" << n + 1
<< "\n n three times==" << 3 * n
<< "\n n twice ==" << n + n
<< "\n nsquared ==" << n*n
<< "\n half of n ==" << n / 2
<< "\n square root of n ==" << sqrt(n)
<< "\n";
// Testing string addition
cout << "Eneter your first name please" << endl;
string String1, String2, String3;
cin >> String1;
cout << "Enter your family name please" << endl;
cin >> String2;
String3 = String1 + " " + String2;
cout << "Welcome" << " " << String3 << endl;
// testing inequalities to strings
string FirstString, SecondString;
cout << "Input First String "
<< endl;
cin >> FirstString;
cout << "Input Second String "
<< endl;
cin >> SecondString;
if (FirstString == SecondString)
cout << "The two words are identical \n";
if (FirstString >= SecondString)
cout << "First word is bigger than second word \n";
if (FirstString <= SecondString)
cout << "Second word is bigger than first word \n";
}
答案 0 :(得分:4)
您从显示.2
的输出中获得提示作为名字(String1
)。在询问名字之前cin
操作在缓冲区上有64.2
,但因为您将值读入int n
,它只读取整数部分64
并离开{{ 1}}在缓冲区上。如果你想要一个整数,将声明n更改为.2
或进行一些输入验证,当你到达名字请求时,应该将缓冲区留空。