Question

我有以下查询：

SELECT transactions.created,
       installments.*,
       transactions.installment_id,
       Sum(transactions.amount) AS s,
       Sum(installments.amount) AS s1
FROM   installments
       LEFT OUTER JOIN transactions
                    ON transactions.installment_id = installments.id
WHERE  installments.customer_id = ?
GROUP  BY installments.id

给了我错误

org.h2.jdbc.JdbcSQLException：列“TRANSACTIONS.CREATED”必须在 GROUP BY列表; SQL语句：

但我需要创建的字段，不想在GROUP_BY中使用它。

Answer 1

SELECT *,s,S1,created
FROM installments
LEFT OUTER JOIN 
(
  SELECT SUM(transactions.amount) AS s, SUM(installments.amount) AS  
  s1,created
  FROM transactions
  GROUP BY created
) A ON A.installment_id = installments.id 
WHERE installments.customer_id=?

Answer 2

将其包含在GROUP BY中修复了语法问题：

SELECT t.created, i.*,
       Sum(t.amount) AS s,
       Sum(i.amount) AS s1
FROM installments i LEFT OUTER JOIN
     transactions t
     ON t.installment_id = i.id
WHERE i.customer_id = ?
GROUP BY i.id, t.created;

但真正的问题是你可能有多个交易。您想要哪个created值？你可能想要更像的东西：

SELECT Min(t.created) as created, i.*,
       Sum(t.amount) AS s,
       Sum(i.amount) AS s1
FROM installments i LEFT OUTER JOIN
     transactions t
     ON t.installment_id = i.id
WHERE i.customer_id = ?
GROUP BY i.id;

我应该注意到s1的计算可能是错误的，因为它会乘以事务数量。我认为更像这样的事情可能就是你的意图：

SELECT t.created, i.*,
       t.amount as s,
       Sum(i.amount) as s1
FROM installments i LEFT OUTER JOIN
     (SELECT t.installment_id, t.created as created,
             SUM(t.amount) as s
      FROM transactions t
      GROUP BY t.installment_id
     ) t
     ON t.installment_id = i.id
WHERE i.customer_id = ?
GROUP BY i.id, t.created, t.amount;

添加要选择的列会给group_by错误

2 个答案: