我试过阅读它上面的文档,我知道我需要使用removeValue()来实现这一点,我只是不知道如何获得点击的位置。我从firebase中删除列表并尝试使用OnItemClick()来表示单击listview中的某些内容时,它将被删除。我觉得这很简单,我只是缺少一些东西。
public class DeleteChoiceListFragment extends Fragment {
DatabaseReference mRootRef = FirebaseDatabase.getInstance().getReference();
DatabaseReference mRestReference = mRootRef.child("restaurants");
List<String> listofrest = new ArrayList<String>();
ListView restaurantListView;
ListAdapter restaurantListAdapter;
public DeleteChoiceListFragment(){}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.restaurant_selection_list_frag,container,false);
restaurantListView = (ListView) view.findViewById(R.id.restaurantListView);
restaurantListAdapter = new FirebaseListAdapter<Restaurants>(getActivity(),Restaurants.class,R.layout.individual_restaurant_name_nocheckbox,mRestReference) {
@Override
protected void populateView(View v, Restaurants model, final int position) {
TextView restName = (TextView) v.findViewById(R.id.restname);
restName.setText(model.getName());
listofrest.add(position,model.getName());
}
};
restaurantListView.setAdapter(restaurantListAdapter);
restaurantListView.setOnItemClickListener(new AdapterView.OnItemClickListener()
{
@Override
public void onItemClick(AdapterView<?> adapterView, View view, int i, long l) {
}
});
return view;
}
}
现在36小时没有睡觉,所以我的大脑已100%死亡。如有必要,我可以提供更多细节
答案 0 :(得分:0)
像这样实现你的setOnItemClickListener
restaurantListView.setOnItemClickListener(new AdapterView.OnItemClickListener()
{
@Override
public void onItemClick(AdapterView<?> adapterView, View view, int i, long l) {
Firebase itemtoRemove = restaurantListAdapter.getRef(i);
itemtoRemove.removeValue();
}
});
添加你的gradle
compile 'com.google.firebase:firebase-core:9.0.1'
compile 'com.google.firebase:firebase-database:9.0.1'