Question

我是php新手，作为测试，我构建了一个测试应用程序，它可以加载存储在数据库中的问题，并将它们显示在一个带有输入类型单选按钮的表中，供用户选择答案。有四个表。问题，答案，用户，userexam。每个表中的行包含一个id作为索引。我遇到的麻烦是在点击提交按钮时将值输入数据库。我将如何循环并将每个问题值添加到数据库中，而无需单独定义每个ID？

 <?php

$getQuestions = "
    SELECT
        *

    FROM
        questions
    WHERE questions.active = '1'

    ORDER BY
        questionID
";
$qResult = mysql_query($getQuestions);

$tableString = "<table>
                    <tr>
                        <th>
                            Questions
                        </th>
                        <th>
                            Answers
                        </th>
                    </tr>";

while ($qRow = mysql_fetch_assoc($qResult)) {
    $getAnswers = "
        SELECT
            *
        FROM
            answers a
        WHERE
            a.questionID = '" . $qRow['questionID'] . "'
        ORDER BY
            a.questionID,
            a.answerNumber
    ";
    $aResult = mysql_query($getAnswers);

    $tableString .= "<tr>
                        <td>" .
                            $qRow['question'] .
                        "</td>
                        <td>";

    while ($aRow = mysql_fetch_assoc($aResult)) {
        if ($aRow['correct'] == 1) {
            $tableString .= "<input name=". $qRow['questionID'] ."
                                type='radio'
                            >" .
                                $aRow['answerValue'] . "<br />";
        } else {

            $tableString .= "<input name=". $qRow['questionID'] ."
                                type='radio'
                            >" .
                                $aRow['answerValue'] . "<br />";
        } 
        $answer=$_POST['. $aRow["answerID"] .'];
        $question=$_POST['. $qRow["questionID"] .'];
        $student=$_POST['userID'];

        // Insert data into mysql 
        $sql="INSERT INTO $userexam(answerID, questionID, userID)VALUES('$answer', '$question', '$student')";
        $result=mysql_query($sql);
    }


}
$tableString .= "</table>";
echo $tableString;
 ?>

Answer 1

在mysql的每个地方使用mysqli（mysql-improved）。

    <?php
//Set database conection
$conection=mysqli_connect('localhost','root','','Your database name');
// Check connection
if (mysqli_connect_errno())
  {
  echo "Failed to connect to MySQL: " . mysqli_connect_error();
  }

$getQuestions = "
    SELECT
        *

    FROM
        questions
    WHERE questions.active = '1'

    ORDER BY
        questionID
";
$qResult = mysqli_query($conection,$getQuestions);

$tableString = "<table>
                    <tr>
                        <th>
                            Questions
                        </th>
                        <th>
                            Answers
                        </th>
                    </tr>";

while ($qRow = mysqli_fetch_assoc($qResult)) {
    $getAnswers = "
        SELECT
            *
        FROM
            answers a
        WHERE
            a.questionID = '" . $qRow['questionID'] . "'
        ORDER BY
            a.questionID,
            a.answerNumber
    ";
    $aResult = mysqli_query($conection,$getAnswers);

    $tableString .= "<tr>
                        <td>" .
                            $qRow['question'] .
                        "</td>
                        <td>";

    while ($aRow = mysqli_fetch_assoc($aResult)) {
        if ($aRow['correct'] == 1) {
            $tableString .= "<input name=". $qRow['questionID'] ."
                                type='radio'
                            >" .
                                $aRow['answerValue'] . "<br />";
        } else {

            $tableString .= "<input name=". $qRow['questionID'] ."
                                type='radio'
                            >" .
                                $aRow['answerValue'] . "<br />";
        } 
        $answer=$_POST['. $aRow["answerID"] .'];
        $question=$_POST['. $qRow["questionID"] .'];
        $student=$_POST['userID'];

        // Insert data into mysql 
        $sql="INSERT INTO userexam(answerID, questionID, userID)VALUES('$answer', '$question', '$student')";
        $result=mysqli_query($conection,$sql);
    }


}
$tableString .= "</table>";
echo $tableString;
mysqli_close($conection);
 ?>

将字段值添加到数据库

1 个答案: