Question

import random

class player():
    def __init__(self, deck):
        self.deck = deck 
        self.hand = []
        self.results = []

    def draw(self,draws):
        for counter in range(0, draws, 1):
            card = random.randrange(0, len(self.deck), 1)
            self.hand.append(self.deck[card])
            del self.deck[card]

    def return_hand(self):
        for returncounter in range(0, len(self.hand), 1):
            self.deck.append(self.hand[returncounter]) 
        for returncounter in range(0, len(self.hand), 1):
            del self.hand[0]

    def simple_function(self):
        for counter in range(0, 3, 1):
            print("Loop", counter)
            self.draw(3)
            print("Hand", simple_cards.hand)
            self.results.extend(self.hand)
            print("Results before return", simple_cards.results)
            self.return_hand()
            print("Results after return", simple_cards.results)
            print("")

simple_cards = player(["A1", "A2", "A3", "B1", "B2", "B3", "C1", "C2", "C3"])

simple_cards.simple_function()
print("Results after function", simple_cards.results)

此代码的示例结果将是

Loop 0
Hand ['B3', 'B2', 'C3']
Results before return ['B3', 'B2', 'C3']
Results after return ['B3', 'B2', 'C3']

Loop 1
Hand ['C2', 'B3', 'A1']
Results before return ['B3', 'B2', 'C3', 'C2', 'B3', 'A1']
Results after return ['B3', 'B2', 'C3', 'C2', 'B3', 'A1']

Loop 2
Hand ['C2', 'B2', 'C1']
Results before return ['B3', 'B2', 'C3', 'C2', 'B3', 'A1', 'C2', 'B2', 'C1']
Results after return ['B3', 'B2', 'C3', 'C2', 'B3', 'A1', 'C2', 'B2', 'C1']

Results after function ['B3', 'B2', 'C3', 'C2', 'B3', 'A1', 'C2', 'B2', 'C1']

如何制作结果3个嵌套列表，如[['B3'，'B2'，'C3']，['C2'，'B3'，'A1']，['C2'，'B2' ，'C1']]

我觉得有一个非常基本的东西，我不理解这里，这个问题肯定已经得到了回答，但我不知道如何通过搜索自己来更好地找到问题。

我尝试追加（self.hand）和扩展（[self.hand]）但是两者都创造了比他们解决的更多问题，导致了

的示例输出

Loop 0
Hand ['B3', 'A2', 'B2']
Results before return [['B3', 'A2', 'B2']]
Results after return [[]]

Loop 1
Hand ['B2', 'B3', 'C3']
Results before return [['B2', 'B3', 'C3'], ['B2', 'B3', 'C3']]
Results after return [[], []]

Loop 2
Hand ['C2', 'B3', 'A2']
Results before return [['C2', 'B3', 'A2'], ['C2', 'B3', 'A2'], ['C2', 'B3', 'A2']]
Results after return [[], [], []]

Results after function [[], [], []]

感谢您的帮助。

Answer 1

您可以使用append将hand的副本添加到results。仅添加hand的问题在于您稍后会使用del对其进行修改，这将反映到打印结果中，如您的示例所示。

如果您将self.results.extend(self.hand)更改为self.results.append(self.hand[:])，则会获得以下输出：

Loop 0
Hand ['A1', 'C2', 'B3']
Results before return [['A1', 'C2', 'B3']]
Results after return [['A1', 'C2', 'B3']]

Loop 1
Hand ['B1', 'B3', 'A1']
Results before return [['A1', 'C2', 'B3'], ['B1', 'B3', 'A1']]
Results after return [['A1', 'C2', 'B3'], ['B1', 'B3', 'A1']]

Loop 2
Hand ['C2', 'B1', 'C1']
Results before return [['A1', 'C2', 'B3'], ['B1', 'B3', 'A1'], ['C2', 'B1', 'C1']]
Results after return [['A1', 'C2', 'B3'], ['B1', 'B3', 'A1'], ['C2', 'B1', 'C1']]

Results after function [['A1', 'C2', 'B3'], ['B1', 'B3', 'A1'], ['C2', 'B1', 'C1']]

Answer 2

您还可以将代码保持为现在的状态，并仅拆分结果。

例如，我假设你的输出是：

output = ['B3', 'B2', 'C3', 'C2', 'B3', 'A1', 'C2', 'B2', 'C1']

所以，你可以这样做：

expected_output = [output[i:i+3] for i in range(0, len(output), 3)]
print(expected_output)

输出：

[['B3', 'B2', 'C3'], ['C2', 'B3', 'A1'], ['C2', 'B2', 'C1']]

因此，为了编辑代码，您只需编辑一行：

self.results.extend(self.hand)至self.results.extend(self.hand[i:i+3] for i in range(0, len(self.hand), 3))

所以你的simple_function()将是：

def simple_function(self):
        for counter in range(0, 3, 1):
            print("Loop", counter)
            self.draw(3)
            print("Hand", simple_cards.hand)
            # The edited line
            self.results.extend(self.hand[i:i+3] for i in range(0, len(self.hand), 3))
            print("Results before return", simple_cards.results)
            self.return_hand()
            print("Results after return", simple_cards.results)
            print("")

编辑后的输出：

Loop 0
Hand ['B1', 'C1', 'C3']
Results before return [['B1', 'C1', 'C3']]
Results after return [['B1', 'C1', 'C3']]

Loop 1
Hand ['C1', 'C3', 'A3']
Results before return [['B1', 'C1', 'C3'], ['C1', 'C3', 'A3']]
Results after return [['B1', 'C1', 'C3'], ['C1', 'C3', 'A3']]

Loop 2
Hand ['C2', 'A3', 'B3']
Results before return [['B1', 'C1', 'C3'], ['C1', 'C3', 'A3'], ['C2', 'A3', 'B3']]
Results after return [['B1', 'C1', 'C3'], ['C1', 'C3', 'A3'], ['C2', 'A3', 'B3']]

Results after function [['B1', 'C1', 'C3'], ['C1', 'C3', 'A3'], ['C2', 'A3', 'B3']]

Python嵌套列表创建

2 个答案: