我正在尝试在分层数据集上编写复杂的CASE
语句。
这是包含样本数据的表格:
Level Parent Child IsDirector
----------------------------------------
0 NULL SteveJobs NO
1 SteveJobs TimCook YES
2 TimCook Greg NO
3 Greg Mark NO
4 Mark Jack NO
4 Mark Kim NO
4 Mark Tyler NO
4 Mark Emma NO
我正在尝试编写一个SQL查询来列出所有人的导演。在上面的示例中,这是SteveJobs担任首席执行官的IT团队的一部分,因此他不是董事。 TimCook是董事,董事是Greg经理。经理是员工。
所以我想写一个查询来选择所有人和Director列中的相关Director Name,条件是如果它是CEO,那么它应该是NULL。
在我的现实生活数据中,有几位CEO,每位董事长下都有多位董事,每位董事都有多位经理。这对我来说真的很复杂。
如果我写一个select *。
,结果应该是这样的Parent Child Director IsDirector
------------------------------------
NULL SteveJobs NULL NO
SteveJobs TimCook TimCook YES
TimCook Greg TimCook NO
Greg Mark TimCook NO
Mark Jack TimCook NO
Mark Kim TimCook NO
Mark Tyler TimCook NO
Mark Emma TimCook NO
这是我为实现这一目的而编写的查询,但它不能按预期工作。
SELECT
A.Parent, A.Child,
CASE A.IsDirector
WHEN 'YES'
THEN A.Child
WHEN 'NO'
THEN CASE
WHEN (A.IsDirector = 'NO' AND A.Parent IS NOT NULL)
THEN A.Parent
ELSE (SELECT
CASE WHEN B.IsDirector = 'YES'
THEN B.Parent
END AS Director
FROM @Org B
WHERE B.Child = A.Parent)
END
END AS Director,
A.IsDirector
FROM
@Org A
答案 0 :(得分:5)
这可以在递归cte
的帮助下生成Declare @YourTable table (Level int,Parent varchar(50),Child varchar(50),IsDirector varchar(50))
Insert into @YourTable values
(0,NULL,'SteveJobs','NO'),
(1,'SteveJobs','TimCook','YES'),
(2,'TimCook','Greg','NO'),
(3,'Greg','Mark','NO'),
(4,'Mark','Jack','NO'),
(4,'Mark','Kim','NO'),
(4,'Mark','Tyler','NO'),
(4,'Mark','Emma','NO')
;with cteP as (
Select Parent
,Child
,Director = case when IsDirector='YES' then CHILD else NULL end
,IsDirector
From @YourTable
Where Parent is null
Union All
Select r.Parent
,r.Child
,Director = case when r.IsDirector='YES' then r.CHILD else p.Director end
,r.IsDirector
From @YourTable r
Join cteP p on r.Parent = p.Child)
Select * from cteP
返回
答案 1 :(得分:2)
DECLARE @Table AS TABLE (Level INT, Parent VARCHAR(100), Child VARCHAR(100), IsDirector VARCHAR(3))
INSERT INTO @Table VALUES
(0,NULL,'SteveJobs','NO')
,(1,'SteveJobs','TimCook','YES')
,(2,'TimCook','Greg','NO')
,(3,'Greg','Mark','NO')
,(4,'Mark','Jack','NO')
,(4,'Mark','Kim','NO')
,(4,'Mark','Tyler','NO')
,(4,'Mark','Emma','NO')
;WITH cte AS (
SELECT
CEO = t.Child
,t.Parent
,t.Child
,Director = CASE WHEN t.IsDirector = 'YES' THEN t.Child ELSE NULL END
,t.IsDirector
FROM
@Table t
WHERE
t.Parent IS NULL
UNION ALL
SELECT
c.CEO
,t.Parent
,t.Child
,Director = CASE WHEN t.IsDirector = 'YES' THEN t.Child ELSE c.Director END
,t.IsDirector
FROM
@Table t
INNER JOIN cte c
ON c.Child = t.Parent
)
SELECT *
FROM
cte
看到你知道CEO是谁(父= NULL)从顶部开始你的递归并走下去。