Question

我查看过与我相同问题的许多帖子，但我仍然无法弄清楚导致此错误发生的原因。我检查了数据类型，它们都是一致的。我检查过某些事情是否未签名，事实并非如此。我浏览了所有列，并将它们的排序规则设置为Table default，并将每个表设置为utf8。我甚至只是完全删除了外键约束并试图再次转发工程师，但它仍然会发生。

        CREATE TABLE IF NOT EXISTS `Melendez`.`Books` (
      `ISBN` VARCHAR(45) NOT NULL,
      `Title` VARCHAR(45) NOT NULL,
      `Author` INT NOT NULL,
      `Publisher` INT NOT NULL,
      `YearPublished` INT NULL,
      `Genre` VARCHAR(45) NOT NULL,
      `Quantity` INT NULL,
      `NumAvailable` INT NULL,
      PRIMARY KEY (`ISBN`),
      INDEX `AuthorFK_idx` (`Author` ASC),
      INDEX `PublisherFK_idx` (`Publisher` ASC),
      INDEX `GenreFK_idx` (`Genre` ASC),
      CONSTRAINT `AuthorFK`
        FOREIGN KEY (`Author`)
        REFERENCES `Melendez`.`Authors` (`AuthorID`)
        ON DELETE NO ACTION
        ON UPDATE NO ACTION,
      CONSTRAINT `PublisherFK`
        FOREIGN KEY (`Publisher`)
        REFERENCES `Melendez`.`Publishers` (`PublisherID`)
        ON DELETE NO ACTION
        ON UPDATE NO ACTION,
      CONSTRAINT `GenreFK`
        FOREIGN KEY (`Genre`)
        REFERENCES `Melendez`.`Genres` (`Genre`)
        ON DELETE NO ACTION
        ON UPDATE NO ACTION)
    ENGINE = InnoDB
    DEFAULT CHARACTER SET = utf8

这是抛出错误的声明。以下是引用的3个表的create table语句：

CREATE TABLE IF NOT EXISTS `Melendez`.`Authors` (
`AuthorID` INT NOT NULL AUTO_INCREMENT,
`FirstName` VARCHAR(45) NOT NULL,
`LastName` VARCHAR(45) NOT NULL,
`MI` VARCHAR(45) NULL,
PRIMARY KEY (`AuthorID`))
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8;

CREATE TABLE IF NOT EXISTS `Melendez`.`Publishers` (
`PublisherID` INT NOT NULL AUTO_INCREMENT,
`PublisherName` VARCHAR(45) NOT NULL,
PRIMARY KEY (`PublisherID`))
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8;

CREATE TABLE IF NOT EXISTS `Melendez`.`Genres` (
`Genre` VARCHAR(45) NOT NULL,
`Section` VARCHAR(45) NOT NULL,
PRIMARY KEY (`Genre`))
ENGINE = InnoDB
DEFAULT CHARACTER SET = utf8;

还有其他我可以寻找的东西吗？我觉得我到处都是。或者也许是我看上去很明显的东西。

正向工程时无法添加外键约束

0 个答案: