我正在尝试从两个不同的单元格中在Excel中编写公式。这就是我所拥有的:
=IF(C5="US",IF(I5="C","1,000",IF(I5="V","2,500",IF(I5="F","2,500",IF(C5="NIFA",IF(I5="C","1,000",IF(I5="V","2,500",IF(I5="F","2,500",IF(C5="West",IF(I5="C","1,000",IF(I5="V","2,000",IF(I5="F","2,000"))))))))))))
以下是我目前的情况:
{{1}}
我对这个公式的问题是,C5中的任何东西都不是美国的“FALSE” - 所有美国都没事。
提前致谢!
答案 0 :(得分:1)
此方法将数据与查找逻辑分开,因此可扩展。这有点类似于Scott Craner的第一个建议(在评论中),但基于2D查找。
如果您按照以下方式排列数据,则可以使用此公式获得答案:
=VLOOKUP($B$6,$A$2:$D$4,MATCH($B$7,$B$1:$D$1,0)+1,0)
请注意,MATCH(...)+1
偏移包含第一组查找值的第一列。 E.g:
其中给出了2500的正确结果:
答案 1 :(得分:0)
这将涵盖所有九种情况:
<script type="text/javascript">
$(document).ready(function () {
$.ajax({
type: "POST",
contentType: "application/json",
data: "{}",
url: "Default.aspx/GetEvents",
dataType: "json",
success: function (data) {
$('div[id*=fullcal]').fullCalendar({
header: {
left: 'prev,next today',
center: 'title',
// right: 'timelineDay,agendaTwoDay,timelineThreeDays,month,agendaWeek,agendaDay,listWeek'//New1-agendaTwoDay
right: 'timelineDay,timelineThreeDays,agendaWeek,month,listWeek'
},
aspectRatio: 1.8,//New4
scrollTime: '00:00', //New5 undo default 6am scrollTime
// defaultView: 'agendaDay',//New2
defaultView: 'timelineDay',//New2
views: {//New3
timelineThreeDays: {
type: 'timeline',
duration: { days: 3 }
}
},
//views: {//New3
// agendaTwoDay: {
// type: 'agenda',
// duration: { days: 2 },
// views that are more than a day will NOT do this behavior by default
// so, we need to explicitly enable it
// groupByResource: true
// //// uncomment this line to group by day FIRST with resources underneath
// //groupByDateAndResource: true
// }
//},
//// uncomment this line to hide the all-day slot
//allDaySlot: false,
schedulerLicenseKey: 'CC-Attribution-NonCommercial-NoDerivatives',//New for Licence
eventLimit: true, // allow "more" link when too many events
editable: true,
//new Resourses
resourceLabelText: 'Rooms',
resources: [
{ id: 'a', title: 'Auditorium A' },
{ id: 'b', title: 'Auditorium B', eventColor: 'green' },
{ id: 'c', title: 'Auditorium C', eventColor: 'orange' },
],
//Resourses
events: $.map(data.d, function (item, i) {
var event = new Object();
event.id = item.EventID;
event.start = new Date(item.StartDate);
event.end = new Date(item.EndDate);
event.title = item.EventName;
event.url = item.Url;
event.ImageType = item.ImageType;
//new
event.resourceId = item.resourceId;
return event;
}), eventRender: function (event, eventElement) {
if (event.ImageType) {
if (eventElement.find('span.fc-event-time').length) {
eventElement.find('span.fc-event-time').before($(GetImage(event.ImageType)));
} else {
eventElement.find('span.fc-event-title').before($(GetImage(event.ImageType)));
}
}
},
loading: function (bool) {
if (bool) $('#loading').show();
else $('#loading').hide();
}
});
},
error: function (XMLHttpRequest, textStatus, errorThrown) {
debugger;
}
});
$('#loading').hide();
$('div[id*=fullcal]').show();
});
function GetImage(type) {
if (type == 0) {
return "<br/><img src = 'Styles/Images/attendance.png' style='width:24px;height:24px'/><br/>"
}
else if (type == 1) {
return "<br/><img src = 'Styles/Images/not_available.png' style='width:24px;height:24px'/><br/>"
}
else
return "<br/><img src = 'Styles/Images/not_available.png' style='width:24px;height:24px'/><br/>"
}
</script>
(并且不需要一个 IF )