Question

PYTHON版本：2.7.5

我正在制作一个小程序，根据用户的输入为用户生成自定义句子。我试图使它成为name（）函数在chooseColour（）函数之前。我之前在代码中调用了name（）函数，但它没有显示出来。我得到的是'你最喜欢的颜色是什么，而不是首先显示的名称（）功能。我将附上代码，如果有人可以复制并更正它，我可以使用您编辑的代码。

# DoC: 07/12/2016
# Creator: Louis Parkes
# Desc: This program will generate a custom sentence depending on the user's imput.

import time

def displayIntro():
    print("Welcome to the CSG (Custom Sentence Generator)")
    print("Please answer the following questions to create the sentence.")
    print("")
    print("Creator: Louis Parkes")
    print("Contact: my-email")
    print("")
    s1()

def displayEnd():
    print("Thanks for using the CSG!")
    print("We hoped you enjoy the experience!")
    rateByUser = int(raw_input("Please rate your experience, 1 being 1 star and 5 being 5 star."))
    if rateByUser == 1 or rateByUser == 2 or rateByUser == 3 or rateByUser == 4:
        print("Please help us improve by emailing 'my-email'")
    elif rateByUser == 5:
        print("Thanks very much for your response! Have a great day!")
    else:
        print("Error: invalid input.")

def s1():
    time.sleep(1)
def s2():
    time.sleep(0.5)

#==================================================================================================

def name():
    forename = ""
    surname = ""
    while forename == 0 and surname == 0:
        forename = raw_input("What is your forename?: ")
        print("")
        time.sleep(1)
        surname = raw_input("What is your surname?: ")
        print("")
        time.sleep(1)
        print("Your name is %s %s! " % (forename, surname))
        time.sleep(0.5)

    return forename
    return surname

    if len(forename) > 5 or len(surname) > 6:
        print("You have a large name, %s! " % (forename, surname))
    elif len(forename) <= 5 or len(surname) <= 6:
        print("You have an average sized name!")
    elif len(forename) > 5 or len(surname) > 6:
        print("You have a small name!")
    else:
        print("Error: Obviously, there is something not right with your input or the code. Please try again. Contact developer if there is a bug.")

s1()
def chooseColour():
    colour = ""
    while len(colour) == 0:
        colour = raw_input("What is your favourite colour?: ")
        s2()
        print("Your favourite colour is %s! " % (colour))

    return colour

displayIntro()
name()
chooseColour()

Answer 1

In [1]: forename = ""

In [2]: forename == 0
Out[2]: False

在名字（）中，你应该测试forename和surname是否为空，不等于0。

您在名称功能中有2个返回。只会执行第一个，之后不执行任何操作。

Answer 2

def name():
    forename = ""
    surname = ""
    while not forename and not surname:
        forename = raw_input("What is your forename?: ")
        print("")
        time.sleep(1)
        surname = raw_input("What is your surname?: ")
        print("")
        time.sleep(1)
        print("Your name is %s %s! " %(forename, surname))
        time.sleep(0.5)


    if len(forename) > 5 or len(surname) > 6:
        print("You have a large name, %s%s! " % (forename, surname))
    elif len(forename) <= 5 or len(surname) <= 6:
        print("You have an average sized name!")
    elif len(forename) > 5 or len(surname) > 6:
        print("You have a small name!")
    else:
        print("Error: Obviously, there is something not right with your input or the code. Please try again. Contact developer if there is a bug.")

    return forename
    return surname

Answer 3

您的name()电话无效，因为：

forename = ""
surname = ""
while forename == 0 and surname == 0:

因为"" != 0永远不满足循环条件，所以不执行循环块。将其更改为：

while forename == "" and surname == "":

或：

while not (forename or surname):

Answer 4

你的问题是在while循环中：

def name():
    forename = ""
    surname = ""
    while forename == "" and surname == "":

您需要将这两个变量与""（空字符串）进行比较，而不是0（整数）

Python代码：函数调用不起作用或代码出错

4 个答案: