Question

我想查询所有带有多个过滤器的产品，例如：

所有产品：[(name: "cookies", brand: "brand x"), (name: "water", brand: "brand y")]

如果我只有一个过滤器，例如(name: "cookies", brand: "brand x")答案很明确：name == \(tuple.name) AND brand == \(tuple.brand)

如果我有多个元组但只有一个属性，那么它也很清楚：

return "name IN {\(["cookies", "water"].joined(separator: ","))}"

但是如何为我的元组数组编写过滤器？一个想法是使用前一个查询Results将每个作为单个name == \(tuple.name) AND brand == \(tuple.brand)获取，并使用此构建一个数组，但我需要Results中的最终结果而不是数组。

也可能这样，但我认为这是不可能的？

return "name::brand IN {\(["cookies::brand x", "water::brand y"].joined(separator: ","))}"

Answer 1

似乎您希望将谓词与NSCompoundPredicate结合使用：

class Product: Object {
    dynamic var name = ""
    dynamic var brand = ""
}

let productsFilter: [(name: String, brand: String)] = [("cookies", "brand x"), ("water", "brand y")]
let subPredicates = productsFilter.map {
    NSPredicate(format: "name = %@ && brand = %@", $0.name, $0.brand)
}
let compoundPredicate = NSCompoundPredicate(orPredicateWithSubpredicates: subPredicates)

let realm = try Realm()
let products = realm.objects(Product.self).filter(compoundPredicate)

领域查询复合过滤器阵列

1 个答案: