Question

当我进行查找和替换时，我正在尝试创建一个正则表达式来包围我视图中所有变量的转义。

当前代码

var methodUrl = CombineUrl("http://something.com", "/task/status/", "dfgd/", "/111", "qqq");

应该成为

echo $this->cust['id'];
echo $this->cust['firstname'];
echo $this->cust['lastname'];
echo $this->cust['postCode'];

$ this-＆gt; cust不一致，因为它可能是$ this-＆gt; quote或$ this-＆gt;订单在不同的视图中

这可能吗？如果可以的话怎么办呢？

Answer 1

如果您想要一个纯PHP解决方案，那么您可以使用preg_replace

/tmp/current.php

echo "some other code";
echo $this->cust['id'];
echo $this->cust['firstname'];
echo $this->cust['lastname'];
echo $this->cust['postCode'];
echo $this->order['size'];
function x() { echo $this->anything['derp']; }

/tmp/regex.php

<?php
$ifile = '/tmp/current.php';
$ofile = '/tmp/new_current.php';

$ifh = fopen($ifile, "r");
$ofh = fopen($ofile, "w");

$regex = '#(\$this->[^]]+])#';
$replace = '$this->escape($1)';

while(($line = fgets($ifh)) !== false) {
    if($new_line = preg_replace($regex, $replace, $line)) {
        fwrite($ofh, $new_line);
    }
    else fwrite($ofh, $line);
}
?>

运行：/tmp/regex.php,yeilds：

echo "some other code";
echo $this->escape($this->cust['id']);
echo $this->escape($this->cust['firstname']);
echo $this->escape($this->cust['lastname']);
echo $this->escape($this->cust['postCode']);
echo $this->escape($this->order['size']);
function x() { echo $this->escape($this->anything['derp']); }

正则表达式替换为快速转义变量

1 个答案: