我一直在研究一个系统编程类的组程序,它将运行某个银行的人会使用的函数。这些功能包括添加银行客户,客户的输出余额等。问题在于添加客户功能。
此函数将在终端和Putty中的无限循环中运行,但是当我在XCode中作为独立程序运行时,循环退出。我,我的小组成员和我们的教授都忽略了该计划有什么问题吗?
#include <stdio.h>
#include <string.h>
#include "./bank.h"
void add(FILE *fp)
{
int i=0;
char firstName[20];
char lastName[20];
float camount;
int prompt;
float samount;
float mamount;
fseek(fp,0,2);
do
{
printf("\nEnter first name: ");
scanf("%s", firstName);
strcpy(bank[i].firstName, firstName);
printf("\nEnter last name: ");
scanf("%s",lastName);
strcpy(bank[i].lastName, lastName);
printf("\nEnter checking account balance: ");
scanf("%f", &camount);
bank[i].checking = camount;
printf("\nEnter savings account balance: ");
scanf("%f", &samount);
bank[i].savings = samount;
printf("\nEnter money market account balance: ");
scanf("%f", &mamount);
bank[i].moneyMarket = mamount;
fwrite(&bank[i],1, sizeof(struct BankInfo),fp);
i++;
printf("Enter 1 to enter another name and 0 to quit: ");
scanf("%d", &prompt);
printf("%d\n", prompt);
} while(prompt == 1);
fclose(fp);
return;
}
执行Makefile后输出的屏幕截图:
旁注:这个函数会写入我们传递的文件,这很好但我们仍然需要它来摆脱循环。
编辑:主要功能的代码: #包括 #包括 #包括 #include“bank.h” #include“definitions.h”
int main()
{
FILE *fp;
int selection;
fp=fopen("bankInfo.dat","ab+");
selection=menu();
while(selection !=6)
{
switch(selection)
{
case 1:
add(fp);
break;
case 2:
// outputBalance(fp);
break;
case 3:
delete(fp);
break;
case 4:
update(fp);
break;
case 5:
// display(fp);
break;
case 6:
exit(0);
break;
default:
printf("Invalid selection\n");
break;
}
}
fclose(fp);
return 0;
}
答案 0 :(得分:3)
您只分配一次选择。这应该可以解决您的问题:
while(true)
{
selection=menu();
switch(selection)
{
case 1:
add(fp);
break;
case 2:
// outputBalance(fp);
break;
case 3:
delete(fp);
break;
case 4:
update(fp);
break;
case 5:
// display(fp);
break;
case 6:
fclose(fp);
exit(0);
break;
default:
printf("Invalid selection\n");
break;
}
}
return 0;