Question

我有这个功能，显示日期之间的年，月和日。在视图表上，我有包含开始和结束日期的数据。如何将该功能集成到我的视图表中？

USE [DB]
GO
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO

alter FUNCTION [db].[GetDateDifference]
(
    @FromDate DATETIME, @ToDate DATETIME
)
RETURNS
 @DateDifference TABLE (
 YEAR INT,  MONTH INT, DAYS INT)
AS
BEGIN
    DECLARE @Years INT, @Months INT, @Days INT, @tmpFromDate DATETIME
    SET @Years = DATEDIFF(YEAR, @FromDate, @ToDate)
     - (CASE WHEN DATEADD(YEAR, DATEDIFF(YEAR, @FromDate, @ToDate),
              @FromDate) > @ToDate THEN 1 ELSE 0 END) 

    SET @tmpFromDate = DATEADD(YEAR, @Years , @FromDate)
    SET @Months =  DATEDIFF(MONTH, @tmpFromDate, @ToDate)
     - (CASE WHEN DATEADD(MONTH,DATEDIFF(MONTH, @tmpFromDate, @ToDate),
              @tmpFromDate) > @ToDate THEN 1 ELSE 0 END) 

    SET @tmpFromDate = DATEADD(MONTH, @Months , @tmpFromDate)
    SET @Days =  DATEDIFF(DAY, @tmpFromDate, @ToDate)
     - (CASE WHEN DATEADD(DAY, DATEDIFF(DAY, @tmpFromDate, @ToDate),
              @tmpFromDate) > @ToDate THEN 1 ELSE 0 END) 

    INSERT INTO @DateDifference
    VALUES(@Years, @Months, @Days)

    RETURN
END

这是我的观察表：

USE [DB]
GO
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO

alter VIEW [db].[View_ServiceTickets]

AS

SELECT  TOP 99 

        ServiceTicketDate,
        BillingDate as 'Project Finished',
        InspectionScheduleDate


FROM        tblServiceTicket INNER JOIN
            tblServiceTicketReport on tblServiceTicket.ServiceTicketID = tblServiceTicketReport.ServiceTicketID 


where  ServiceTicketDate > '2016'
order by ServiceTicketDate desc

GO

非常感谢

Answer 1

我看到你的函数的返回数据类型是一个表，所以你使用它作为一个表。你可以测试以下内容：

alter VIEW [db].[View_ServiceTickets]

AS

SELECT  TOP 99 

    ServiceTicketDate,
    BillingDate as 'Project Finished',
    InspectionScheduleDate,
    d.*


FROM        tblServiceTicket INNER JOIN
        tblServiceTicketReport on tblServiceTicket.ServiceTicketID = tblServiceTicketReport.ServiceTicketID 
        OUTER APPLY(SELECT YEAR,MONTH,DAYS FROM [db].[GetDateDifference](ServiceTicketDate,BillingDate)) d


where  ServiceTicketDate > '2016'
order by ServiceTicketDate desc

视图表中的SQL函数

1 个答案: