我正在尝试将我的程序设置为异常句柄,如果用户没有输入任何内容,那么他们将收到错误消息"错误,输入大于0的金额"或"错误,输入1,2或3"。截至目前,如果用户只是点击"输入"没有输入....
import java.util.Scanner;
import java.util.*;
import java.text.DecimalFormat;
public class Candleline
{
public static void main(String[] args)
{
//initiate scanner
Scanner input = new Scanner(System.in);
System.out.println("\tCandleLine - Candles Online");
System.out.println(" ");
//declare variables and call methods
double candleCost = getCandleCost();
int shippingType = getShippingType();
double shippingCost = getShippingCost(candleCost, shippingType);
output(candleCost, shippingCost);
}
public static double getCandleCost()
{
//get candle cost and error check
Scanner input = new Scanner(System.in);
boolean done = false;
String inputCost;
double candleCost = 0;
while(!done)
{
System.out.print("Enter the cost of the candle order: ");
try
{
inputCost = input.next();
candleCost = Double.parseDouble(inputCost);
if (inputCost == null) throw new InputMismatchException();
if (candleCost <=0) throw new NumberFormatException();
done = true;
}
catch(InputMismatchException e)
{
System.out.println("Error, enter a dollar amount greater than 0");
input.nextLine();
}
catch(NumberFormatException nfe)
{
System.out.println("Error, enter a dollar amount greater than 0");
input.nextLine();
}
}
return candleCost;
}
public static int getShippingType()
{
//get shipping type and error check
Scanner input = new Scanner(System.in);
boolean done = false;
String inputCost;
int shippingCost = 0;
while(!done)
{
System.out.println(" ");
System.out.print("Enter the type of shipping: \n\t1) Priority(Overnight) \n\t2) Express (2 business days) \n\t3) Standard (3 to 7 business days) \nEnter type number: ");
try
{
inputCost = input.next();
shippingCost = Integer.parseInt(inputCost);
if (inputCost == null) throw new InputMismatchException();
if (shippingCost <=0 || shippingCost >= 4) throw new NumberFormatException();
done = true;
}
catch(InputMismatchException e)
{
System.out.println("Error, enter a 1, 2 or 3");
input.nextLine();
}
catch(NumberFormatException nfe)
{
System.out.println(" ");
System.out.println("Error, enter a 1, 2 or 3");
input.nextLine();
}
}
return shippingCost;
}
public static double getShippingCost(double candleCost, int shippingType)
{
//calculate shipping costs
double shippingCost = 0;
if (shippingType == 1)
{
shippingCost = 16.95;
}
if (shippingType == 2)
{
shippingCost = 13.95;
}
if (shippingType == 3)
{
shippingCost = 7.95;
}
if (candleCost >= 100 && shippingType == 3)
{
shippingCost = 0;
}
return shippingCost;
}
public static void output(double fCandleCost, double fShippingCost)
{
//display the candle cost, shipping cost, and total
Scanner input = new Scanner(System.in);
DecimalFormat currency = new DecimalFormat("$#,###.00");
System.out.println("");
System.out.println("The candle cost of " + currency.format(fCandleCost) + " plus the shipping cost of " + currency.format(fShippingCost) + " equals " + currency.format(fCandleCost+fShippingCost));
}
}
答案 0 :(得分:0)
替换input.next();
使用input.nextLine();
答案 1 :(得分:0)
您可以编写一个method
来验证输入,然后再继续。如果用户输入无效的内容,它可以继续询问输入。例如。下面的示例演示了如何验证integer
输入:
private static int getInput(){
System.out.print("Enter amount :");
Scanner scanner = new Scanner(System.in);
int amount;
while(true){
if(scanner.hasNextInt()){
amount = scanner.nextInt();
break;
}else{
System.out.println("Invalid amount, enter again.");
scanner.next();
}
}
scanner.close();
return amount;
}