在for循环中,我想根据循环控制变量确定要采取的操作,从我的评论中可以看出它很棘手
public void someFunction(int numberOfReps)
{
for (int i = 0; i < numberOfReps; i++)
{
//if it's first execution; do that, but also do it if it's fourth or eights etc into infinity
//if it's second execution; do that, but also do it if it's fifth or ninth etc into infinity
//if it's third execution; do that, but also do it if it's sixth or tenth etc into infinity
}
}
答案 0 :(得分:0)
使用模数运算符%4:
0%4为0,4%4为0,8%4为0 ...所以它满足第一个条件
1%4为1,5%4为1 ...因此它满足第二个条件 ... ..
我相信你可以弄清楚剩下的。
提示:使用 continue 关键字跳过执行其余循环。
答案 1 :(得分:0)
对于您需要检查的每个条件,您必须有某种条件声明。
您可以在Java中使用多个条件和OR运算符exports.config = {
jasmineNodeOpts: {
grep: '@smoke',
}
};
来确定是否满足其中一个条件。另外值得注意的是,您可以使用AND运算符||
来确定是否已满足这两个条件。
例如:假设您需要确定数字是否等于1或是3的倍数(3,6,9,12等)
&&
答案 2 :(得分:0)
是这样的吗?
public void someFunction(int numberOfReps)
{
for (int i = 1; i < numberOfReps; i++)
{
if(i==1 || i%4==0){
doFirst();
//if it's first execution; do that, but also do it if it's fourth or eights etc into infinity
}else if(i==2 || i%5==0){
doSecond();
//if it's second execution; do that, but also do it if it's fifth or ninth etc into infinity
}else if(i==3 || i%6==0){
doThird();
//if it's third execution; do that, but also do it if it's sixth or tenth etc into infinity
}
}
}