在Firebase

时间:2016-12-08 19:34:30

标签: java android listview firebase

我见过其他人问过这个问题,但在我看来,我已经做了所有需要的事情,而我仍然没有让它发挥作用。我在类错误中找到名字的No setter / field。 Database 我包括了我的数据库的图片。这非常简单。

public class Restaurants {
private String name;

public Restaurants(){}

public Restaurants(String name)
{
    this.name = name;
}

public String getRestaurant()
{
    return name;
}
public void setRestaurant(String name)
{
    this.name = name;
}
@Override
public String toString() {
    return "Restaurants" +
    "name" + name;
    }
}

我有我的吸气剂和制定者,所以理论上应该有效。

public class RestaurantSelectionList extends Fragment {

    DatabaseReference mRootRef = FirebaseDatabase.getInstance().getReference();
    DatabaseReference mRestReference = mRootRef.child("restaurants");

    List<String>listofrest = new ArrayList<String>();
    ListView restaurantListView;
    ListAdapter restaurantListAdapter;


    public RestaurantSelectionList(){}

    @Override
    public View onCreateView(LayoutInflater inflater,  ViewGroup container, Bundle savedInstanceState) {
        View view = inflater.inflate(R.layout.restaurant_selection_list_frag,container,false);
        restaurantListView = (ListView) view.findViewById(R.id.restaurantListView);
        restaurantListAdapter = new FirebaseListAdapter<Restaurants>(getActivity(),Restaurants.class,R.layout.individual_restaurant_name,mRestReference) {
            @Override
            protected void populateView(View v, Restaurants model, int position) {
                TextView restName = (TextView) v.findViewById(R.id.restname);
                restName.setText(model.getRestaurant());

                listofrest.add(position,model.getRestaurant());
            }
        };

        restaurantListView.setAdapter(restaurantListAdapter);

        restaurantListView.setOnItemClickListener(new AdapterView.OnItemClickListener()
        {
            @Override
            public void onItemClick(AdapterView<?> adapterView, View view, int i, long l) {
                Toast.makeText(getActivity(), "test", Toast.LENGTH_SHORT).show();
            }
        });
        return view;
    }

这是调用它的代码。请告诉我我错过了什么。这是持续4个小时的看法。

1 个答案:

答案 0 :(得分:1)

请将您的模型类更改为:

public class Restaurants {

    private String name;

    public Restaurants(){}

    public void setName(String name)
    {
        this.name = name;
    }

    public String getName()
    {
        return name;
    }

    @Override
    public String toString() {
        return "Restaurants" + "name" + name;
    }
}