Question

我试图根据最接近的日期更改$showThis。我如何比较时差？目前$interval1 > $interval2不起作用。我知道差异正在计算中，但我不确定如何比较两者。

$currentTime = new DateTime("now");
$wednesday = new DateTime('wednesday 10:59pm');
$saturday = new DateTime('saturday 10:59pm');
$interval1 = $currentTime->diff($wednesday);
$interval2 = $currentTime->diff($saturday);

if($interval1 > $interval2){
    $showThis = $saturday->format('D m/d/Y h:i A');
}
if($interval1 < $interval2){
    $showThis = $wednesday->format('D m/d/Y h:i A');
}

Answer 1

使用getTimestamp方法。

$interval1 = $wednesday->getTimestamp() - $currentTime->getTimestamp();
$interval2 = $saturday->getTimestamp() - $currentTime->getTimestamp();

Answer 2

您应该在将比较之前将其添加到0日期，将间隔转换为秒：

$currentTime = new DateTime("now");
$wednesday = new DateTime('wednesday 10:59pm');
$saturday = new DateTime('saturday 10:59pm');

$interval1 = $currentTime->diff($wednesday);
$interval2 = $currentTime->diff($saturday);

$seconds1 = date_create('@0')->add($interval1)->getTimestamp();
$seconds2 = date_create('@0')->add($interval2)->getTimestamp();

if ($seconds1 > $seconds2){
    $showThis = $saturday->format('D m/d/Y h:i A');
}
else {
    $showThis = $wednesday->format('D m/d/Y h:i A');
}

echo $showThis;

Php - 比较当前日期的两个未来日期距离

2 个答案: