Question

我创建了一个目录，其中存储了一些图像。现在，要将其压缩为单个.zip文件，我使用以下代码：

private static void zipDir(String zipFileName, String dir) throws Exception {
    File dirObj = new File(dir);
    ZipOutputStream out = new ZipOutputStream(newFileOutputStream(zipFileName));
    addDir(dirObj, out);
    out.close();
}

static void addDir(File dirObj, ZipOutputStream out) throws IOException {
    File[] files = dirObj.listFiles();
    byte[] tmpBuf = new byte[1024];

    for (int i = 0; i < files.length; i++) {
      if (files[i].isDirectory()) {
        addDir(files[i], out);
        continue;
     }
     FileInputStream in = new FileInputStream(files[i].getAbsolutePath());
     System.out.println(" Adding: " + files[i].getAbsolutePath());
      out.putNextEntry(new ZipEntry(files[i].getAbsolutePath()));
      int len;
      while ((len = in.read(tmpBuf)) > 0) {
        out.write(tmpBuf, 0, len);
      }
      out.closeEntry();
      in.close();
    }
  }

我从以下来源获取此代码：http://www.java2s.com/Code/Java/File-Input-Output/Makingazipfileofdirectoryincludingitssubdirectoriesrecursively.htm

当我运行此代码时，在指定目录中创建一个具有指定名称的.zip文件，但是当我尝试在Android或PC上使用任何软件（winzip等）打开它时，它会显示错误消息：该文件已损坏或无效的zip文件＆＃34;

任何帮助都将不胜感激。

Answer 1

我正在考虑删除这个问题。但它代表了一个相当有趣的读物。在创建.zip文件时，我指定了与我想要压缩的目录相同的目录。这导致无限循环。更改.zip目录可以解决问题。

Answer 2

我是这样的意思：

private static void zipDir(String zipFileName, String dir) throws Exception {
    List<String> files = buildFileList(dir, "");
    ZipOutputStream out = new ZipOutputStream(newFileOutputStream(zipFileName));
    zipFiles(files, out);
    out.close();
}

static List<String> buildFileList(String path, String filter) {
    List<String> lstFile = new ArrayList<String>();
    File[] files = new File(path).listFiles();

    if (files != null) {
        for (int i = 0; i < files.length; i++) {
            File f = files[i];
            if (f.isFile()) {
                if (filter.length() == 0 || f.getName().matches(filter))
                    lstFile.add(f.getAbsolutePath());

            } else if (f.isDirectory() && f.getPath().indexOf("/.") == -1)
                lstFile.addAll(getFilePaths(f.getAbsolutePath(), filter));
        }
    }
    return lstFile;
}

static void zipFiles(List<String> files, ZipOutputStream out) throws IOException {
    byte[] tmpBuf = new byte[1024];

    for (String file : files) {
      if (new File(file).isDirectory()) {
        continue;
     }
     FileInputStream in = new FileInputStream(file);
     System.out.println(" Adding: " + file);
      out.putNextEntry(new ZipEntry(file));
      int len;
      while ((len = in.read(tmpBuf)) > 0) {
        out.write(tmpBuf, 0, len);
      }
      out.closeEntry();
      in.close();
    }
}

Android Zipping文件

2 个答案: