Question

我需要一个查询，它可以在10天内为客户提供相同生产订单的结果。由于生产管理，制造商不喜欢在短时间内多次订购相同产品的客户（例如10天对我而言）

以下是示例订单表代码。

DECLARE @Orders TABLE(Customer VARCHAR(50), Product VARCHAR(50), OrderDate DATE)

INSERT INTO @Orders VALUES
('A Company','w102', '2016-10-10'),('A Company','w102', '2016-10-12'),('A Company','w102', '2016-10-24'),
('B Company','w302', '2016-11-11'),('B Company','w302', '2016-11-15'),('B Company','w302', '2016-11-17'),
('C Company','w404', '2016-11-17'),('C Company','w404', '2016-11-24'),('C Company','w405', '2016-11-24')

select * from @Orders ORDER BY Customer, OrderDate

那么如何才能在10天内获得客户订单列表相同的内容？

Answer 1

您可以在原始订单的10天内使用EXISTS检查与同一客户和产品的其他订单：

SELECT  *
FROM    @Orders AS o
WHERE   EXISTS
        (   SELECT  1
            FROM    @Orders AS o2
            WHERE   o2.Customer = o.Customer
            AND     o2.Product = o.Product
            AND     o2.OrderDate > o.OrderDate
            AND     o2.OrderDate <= DATEADD(DAY, 10, o.OrderDate)
        );

给出了：

Customer    Product     OrderDate
---------------------------------------
A Company   w102        2016-10-10
B Company   w302        2016-11-11
B Company   w302        2016-11-15
C Company   w404        2016-11-17

这只会返回两个订单中第一个订单的详细信息，如果您需要下一个订单的详细信息（例如日期），那么您可以使用CROSS APPLY：

SELECT  o.Customer,
        o.Product,
        FirstOrderDate = o.OrderDate,
        NextOrderDate = o2.OrderDate
FROM    @Orders AS o
        CROSS APPLY
        (   SELECT  TOP 1 o2.OrderDate
            FROM    @Orders AS o2
            WHERE   o2.Customer = o.Customer
            AND     o2.Product = o.Product
            AND     o2.OrderDate > o.OrderDate
            AND     o2.OrderDate <= DATEADD(DAY, 10, o.OrderDate)
            ORDER BY o2.OrderDate
        ) AS o2;

给出了：

Customer    Product FirstOrderDate  NextOrderDate
------------------------------------------------
A Company   w102    2016-10-10      2016-10-12
B Company   w302    2016-11-11      2016-11-15
B Company   w302    2016-11-15      2016-11-17
C Company   w404    2016-11-17      2016-11-24

仅在SQL Server 2012及更高版本中可用的第三个版本将使用LEAD()或LAG()：

SELECT  o.Customer,
        o.Product,
        o.FirstOrderDate,
        o.NextOrderDate
FROM    (   SELECT  o.Customer,
                    o.Product,
                    FirstOrderDate = o.OrderDate,
                    NextOrderDate = LEAD(o2.OrderDate) OVER(PARTITION BY Customer, Product ORDER BY o.OrderDate)
            FROM    @Orders AS o
            WHERE   o2.Customer = o.Customer
        ) AS o
WHERE   o.NextOrderDate > o.FirstOrderDate
AND     o.NextOrderDate <= DATEADD(DAY, 10, o.FirstOrderDate);

查找客户订单频率

1 个答案: