Question

我正面临着这个奇怪但基本的apache-drill SQL问题，操作的简单划分给出了错误的结果，如下所示：

0: jdbc:drill:drillbit=localhost> SELECT 'Test' FROM (VALUES(1));
+---------+
| EXPR$0  |
+---------+
| Test    |
+---------+
1 row selected (1.027 seconds)
0: jdbc:drill:drillbit=localhost> select 10/100 from (VALUES(1));
+---------+
| EXPR$0  |
+---------+
| 0       |
+---------+
1 row selected (0.67 seconds)
0: jdbc:drill:drillbit=localhost> select 100/10 from (VALUES(1));
+---------+
| EXPR$0  |
+---------+
| 10      |
+---------+
1 row selected (0.662 seconds)
0: jdbc:drill:drillbit=localhost> select 10/11 from (VALUES(1));
+---------+
| EXPR$0  |
+---------+
| 0       |
+---------+
1 row selected (0.649 seconds)
0: jdbc:drill:drillbit=localhost> select cast(10/11 as float) from (VALUES(1));
+---------+
| EXPR$0  |
+---------+
| 0.0     |
+---------+
1 row selected (0.74 seconds)
0: jdbc:drill:drillbit=localhost> select cast(10/11 as double) from (VALUES(1));
+---------+
| EXPR$0  |
+---------+
| 0.0     |
+---------+
1 row selected (0.691 seconds)
0: jdbc:drill:drillbit=localhost> select cast(10*100/11 as double) from (VALUES(1));
+---------+
| EXPR$0  |
+---------+
| 90.0    |
+---------+
1 row selected (0.72 seconds)
0: jdbc:drill:drillbit=localhost> select cast(10*100/11 as double)/100 from (VALUES(1));
+---------+
| EXPR$0  |
+---------+
| 0.9     |
+---------+

钻取版本为1.6和1.8（两者都试过）。即使round也无济于事。有什么工作吗？

Answer 1

这是整数运算 11/4 = 2（和提醒= 3）

您必须将其中一个值转换为请求的类型。

select cast(x as float)/y

Apache Drill SQL：当分子＆gt;时，除法失败分母

1 个答案: