Question

我有一个字符串＆＃39;＆＃34;＆amp;＆＃34; abc1＆＃34;＃＆＃34; 1＆＃34;＆amp;＆＃34;＆＃34; abc2＆＃34;＃＆＃34; 2＆＃34;＆安培;＆＃34;＆＃34; ABC3＆＃34;＃＆＃34; 3＆＃34;＆安培;＆＃34;＆＃34; ABC1＆＃34;＃＆＃34; 4

我只想将每个int提取到单独的变量中。目前我有注意endtext =＆＃34;＃＆＃34; 和endnum =＆＃34;＆amp;＆＃34;

WHILE @N < LEN(@TextField)
BEGIN

SET @read1 = (
SELECT SUBSTRING(@TextFieled, 
CHARINDEX(@endtext, @TextFieled) + @N --Increment 2 so skips to next "
, CHARINDEX(@endnum,@TextFieled) - CHARINDEX(@endtext, @TextFieled)) --MANY         CHARS TO GO FOR
)

SELECT @read1

SET @N = @N + CHARINDEX(@read1, @TextFieled) --next strating point
END

但它不仅仅返回数字。我认为问题在于我想要选择的nums位于重复的字符串中，因此我不确定如何改变我的循环以跳过。

Answer 1

为了便于阅读和调试，请使用变量来存储CHARINDEX

DECLARE 
    @N int = 2, 
    @TextField varchar(100) = '"&"abc1"#"1"&""abc2"#"2"&""abc3"#"3"&""abc1"#"4',
    @read1 varchar(10),
    @endtext varchar(3) = '"#"',
    @endnum varchar(3) = '"&"',
    @Start int,
    @Finish int


WHILE @N < LEN(@TextField)
BEGIN

SET @Start = CHARINDEX(@endtext, @TextField, @N)
SET @Finish =CHARINDEX(@endnum, @TextField, @N)
IF @Finish = 0 SET @Finish = LEN(@TextField) + 1

SET @read1 = (SELECT SUBSTRING(@TextField, @Start + 3, @Finish - @Start - 3))
SELECT @read1 xRead

SET @N = @Finish + 1 --next strating point
END

选择在字符串中重复多次的两个字符之间的字符串

1 个答案: