android：显示1个正确和错误的项目

Question

    Cursor cursor = db.rawQuery("select * from sentmessages", null);
    /*cursor.moveToFirst();
    dataToInsert = dataToInsert + cursor.getString(1) + '\n';*/

    cursor.moveToFirst();
    dataToInsert = dataToInsert.concat(String.valueOf("aaaa")).concat(String.valueOf("\n"));



    String dataToInsert = "";
    cursor.moveToFirst();
    dataToInsert = dataToInsert.concat(String.valueOf("bbbb")).concat(String.valueOf("\n"));

    cursor.moveToFirst();
    dataToInsert = dataToInsert.concat(String.valueOf("cccc")).concat(String.valueOf("\n"));

    cursor.moveToFirst();
    dataToInsert = dataToInsert.concat(String.valueOf("dddd")).concat(String.valueOf("\n"));

    shdb.setText(dataToInsert);

下面的代码显示

  

aaaa和......

我要替换哪些代码才能显示

  

aaaa，bbbb，cccc，dddd

Answer 1

用此替换您的代码并尝试

Cursor cursor = db.rawQuery("select * from sentmessages", null);
String dataToInsert = "";
cursor.moveToFirst();
dataToInsert = dataToInsert.concat(String.valueOf("aaaa")).concat(String.valueOf(", "));

cursor.moveToFirst();
dataToInsert = dataToInsert.concat(String.valueOf("bbbb")).concat(String.valueOf(", "));

cursor.moveToFirst();
dataToInsert = dataToInsert.concat(String.valueOf("cccc")).concat(String.valueOf(", "));

cursor.moveToFirst();
dataToInsert = dataToInsert.concat(String.valueOf("dddd")).concat(String.valueOf(", "));

shdb.setText(dataToInsert);