Question

我正在尝试使用android中的volley将post参数作为用户名和图像发送为multiform数据。我正在创建正文以及发送参数，但似乎邮政服务的主体以某种方式覆盖了从服务器给出的参数。我使用自定义请求类，其中编写的代码如下：

public abstract class CustomJsonRequest<T> extends Request<T> {
 ................

  @Override
protected Map<String, String> getParams() throws AuthFailureError {
   // return super.getParams();
    HashMap<String, String> map = new HashMap<>();
    map.put("userName", requestParameters.get("userName"));

    return map;
}

public byte[] getBody() throws AuthFailureError {
    return createPostBody(requestParameters).getBytes();
}


private String createPostBody(Map<String, String> params) {
    StringBuilder sbPost = new StringBuilder();
    if (params != null) {

        // for (String key : params.keySet()) {
        if (params.get("image") != null) {
            sbPost.append("\r\n" + "--" + BOUNDARY + "\r\n");
            sbPost.append("Content-Disposition: form-data; name=\"" + "image" + "\"" + "\r\n\r\n");
            sbPost.append(params.get("image"));
        }
        //}
    }
    return sbPost.toString();
}

 }

在调试时我可以看到没有调用getParameters。我的目标是使用android中的volley发送带有图像的post参数作为其post体。在Ios中，它使用alamofire并通过以下代码成功上传。

  func uploadImage(userImage: UIImage, completion: (result: RestResultType) -> Void) {
    let parameters = ["userName": localData.getAccessToken()]
    let url = domain + RestExt.imageUpload.rawValue

    Alamofire.upload(.POST, url, multipartFormData: {
        multipartFormData in

        let imageData = UIImageJPEGRepresentation(userImage, 0.5)
        if(imageData == nil) {
            completion(result: .Error(e: method(code: "ImageConversionError",message: "")))
            return
        }

        multipartFormData.appendBodyPart(data: imageData!, name: "image", fileName: "image.png", mimeType: "image/png")
        for (key, value) in parameters {
            multipartFormData.appendBodyPart(data: value.dataUsingEncoding(NSUTF8StringEncoding)!, name: key)
        }

        }, encodingCompletion: {
            encodingResult in

            switch encodingResult {
            case .Success(let upload, _, _):
                upload.responseJSON {
                    response in
                    switch response.result {
                    case .Success(let JSONResponse) :
                        let response = JSONResponse as! NSDictionary
                        let error = response.objectForKey("error") as? NSDictionary
                        if(error != nil) {
                            completion(result: .Error(e: method(JSONDictionary: error!)))
                        }
                        else {
                            completion(result: .Success(r: response))
                        }

                    case .Failure(let err):
                       }
                }
            case .Failure(let encodingError):
                print(encodingError)
            }
    })
}

Answer 1

我曾经发送过转换为字符串的图像。这对我有用......

public static void uploadImage(final String userName, final Bitmap bitmap, final Bitmap thumbBitmap, final Activity activity) {
    //Showing the progress dialog

    String UPLOAD_URL = "your/url/address";
    RequestQueue queue = Volley.newRequestQueue(activity);
    final String image = getStringImage(bitmap);

    final ProgressDialog loading = ProgressDialog.show(activity, "Uploading...", "Please wait...", false, false);
    StringRequest stringRequest = new StringRequest(Request.Method.POST, UPLOAD_URL,
            new Response.Listener<String>() {
                @Override
                public void onResponse(String s) {

                }
            },
            new Response.ErrorListener() {
                @Override
                public void onErrorResponse(VolleyError volleyError) {
                    //Dismissing the progress dialog
                    loading.dismiss();
                }
            }) {

        protected Map<String, String> getParams() throws AuthFailureError {
            //Converting Bitmap to String
            String image = getStringImage(bitmap);
            //Getting Image Name

            String name = "user_name";

            //Creating parameters
            Map<String, String> params = new Hashtable<String, String>();

            //Adding parameters
            params.put("image", image);
            params.put("userName", name);

            //returning parameters
            return params;
        }
    };

    //Adding request to the queue
    queue.add(stringRequest);
}

   public static String getStringImage(Bitmap bmp) {
    ByteArrayOutputStream baos = new ByteArrayOutputStream();
    bmp.compress(Bitmap.CompressFormat.JPEG, 100, baos);
    byte[] imageBytes = baos.toByteArray();
    String encodedImage = Base64.encodeToString(imageBytes, Base64.DEFAULT);

    return encodedImage;
}

Answer 2

尝试使用截击的多部分请求。

请参阅以下链接 enter link description here

使用用户名作为post参数的图像上传和在android volley中的http post服务中的图像作为正文

2 个答案: