我的问题是无法向邮件发送可下载的链接, 实际上我选择了两个变量,我已经获得了(userID,userPic)的值,所以现在我无法将链接发送到邮件
<?php
if(isset($_POST['useremail'])) {
$uploadID = $_GET['uploadID'];
$filename = $_GET['userPic'];
$memberID =$_SESSION['memberID'];
$email = $_SESSION['email'];
$mail = $_POST['useremail'];
$stmt = $DB_con->prepare('INSERT INTO share(uploadID,useremail,userPic,memberID) VALUES(:uploadID, :useremail,:userPic, :memberID)');
$stmt->bindParam(':uploadID',$uploadID);
$stmt->bindParam(':useremail',$mail);
$stmt->bindParam(':userPic',$filename);
$stmt->bindParam(':memberID',$memberID);
if($stmt->execute())
{
$successMSG = "succesfully sended mail ..." ;
header("location:user.php");
}
> Blockquote
$url = "<p>
<a href='http://www.adroitsws.com/data_transfer/download.php?filename=<?php echo $row['userPic']; ?>'>http://www.adroitsws.com/data_transfer/download.php?filename=<?php echo $row['userPic']; ?></a></p>"
$email_from =$email;
$email_subject = "Your email subject line";
function died($error) {
// your error code can go here
echo "We are very sorry, but there were error(s) found with the form you submitted. ";
echo "These errors appear below.<br /><br />";
echo $error."<br /><br />";
echo "Please go back and fix these errors.<br /><br />";
die();
}
if(!isset($_POST['useremail']) ) {
died('We are sorry, but there appears to be a problem with the form you submitted.');
}
$email_to = $_POST['useremail']; // required
$error_message = "";
$email_exp = '/^[A-Za-z0-9._%-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}$/';
if(!preg_match($email_exp,$email_to)) {
$error_message .= 'The Email Address you entered does not appear to be valid.<br />';
}
function clean_string($string) {
$bad = array("content-type","bcc:","to:","cc:","href");
return str_replace($bad,"",$string);
}
$email_message .= "mail: ".clean_string($email_to)."\n";
// create email headers
$headers = 'From: '.$email_from."\r\n".
'Reply-To: '.$email_to."\r\n" .
'X-Mailer: PHP/' . phpversion();
@mail( $email_to, $email_subject,$url, $email_message, $headers);
?>
答案 0 :(得分:1)
您可以查看以下链接,其中显示了如何在php中发送带附件的邮件。
另请注意,在您的代码中存在错误。请通过以下代码替换您的$ URL并检查。
$url = "<p> <a href=http://www.adroitsws.com/data_transfer/download.php?filename=".$row['userPic'].">"
. "http://www.adroitsws.com/data_transfer/download.php?filename=".$row['userPic']."</a></p>";