verilog中unblock赋值的返回值是多少？

Question

我在verilog源代码中发现了这个语句，我不知道它是什么意思？ unblock赋值的返回值是多少？是NUMBER_OF_INPUT_WORDS-1？

assign axis_tready = ((mst_exec_state == WRITE_FIFO) && (write_pointer <= NUMBER_OF_INPUT_WORDS-1));

Answer 1

此语句将1/0分配给axis_ready。

您的代码与下面详细说明的代码相同。

wire cmp1, cmp2;

assign cmp1 = (mst_exec_state == WRITE_FIFO); // Gives output in 0/1
assign cmp2 = (write_pointer <= NUMBER_OF_INPUT_WORDS-1); // Gives output in 0/1
assign axis_tready = cmp1 & cmp2;