我被卡在了我的LUIS对话框中。我试图通过
调用FormDialog[LuisIntent("GetRestaurant")]
public async Task GetRestaurant(IDialogContext context, LuisResult result) {
try {
FormDialog<AddressForm> addressForm = new FormDialog<AddressForm>(new AddressForm(), AddressForm.BuildAddressForm, FormOptions.PromptInStart);
AddressForm address = new AddressForm();
context.Call(addressForm, AddressFormCompleteAsync);
}
在调用之后,我的模拟器在我的表单对话框中返回第一个提示符(哪个城市?),并将下一个输入作为Luis输入并尝试将其与LuisIntent匹配。
我的表格如下:
[Serializable]
public class AddressForm {
[Prompt(new string[] { "Which city?" })]
public string City { get; set; }
[Prompt("Which street?")]
public string Street { get; set; }
[Prompt("Which number?")]
public string Number { get; set; }
public static IForm<AddressForm> BuildAddressForm() {
IForm<AddressForm> addressFrom = new FormBuilder<AddressForm>()
.Field(nameof(City), validate: ValidateCityInformation)
.Field(nameof(Street))
.Field(nameof(Number), validate: ValidateNumberInformation, active: NumberEnabled)
.Build();
return addressFrom;
}
我的简历方法还没有做太多工作,仅用于调试。
private async Task AddressFormCompleteAsync(IDialogContext context, IAwaitable<AddressForm> result) {
var adress = await result;
context.Wait(MessageReceived);
}
如何留在FormDialog中,不要跳回我的LuisDialog? 如果我需要使用context.Forward(),那么我的AddressForm类是否需要是IDialog类型,我如何在AddressFrom类中处理IAwaitable?
感谢您的帮助。
答案 0 :(得分:2)
我现在想出了答案。它跳出FormDialog,因为提示(在Channel中显示)计为调用方法的一个消息(我称之为LuisDialog),因此FormDialog和LuisDialog获取context.Done。我必须更加小心对话流程。