Question

我的WebApiConfig

中有以下路线

        config.Routes.MapHttpRoute(
            name: "PaginateMessages",
            routeTemplate: "api/Message/PaginateMessages/{conversationId}/{lastMessageId}",
            defaults: new { controller = "Message", action = "PaginateMessages", conversationId = RouteParameter.Optional, lastMessageId = RouteParameter.Optional }
        );

我在Message控制器中有相应的操作：

    [HttpGet]
    public async Task<List<MessageDTO>> PaginateMessages(int conversationId, int lastMessageId)
    {            
        return null;
    }

然而，当我尝试点击端点时，我得到了404：

http://localhost:60162/api/Message/PaginateMessages/71/150

如上所示，是否不可能有多个路由参数？

Answer 1

您需要在路线模板中添加{controller}和{action}。

config.Routes.MapHttpRoute(
    name: "PaginateMessages",
    routeTemplate: "api/{controller}/{action}/{conversationId}/{lastMessageId}",
    defaults: new {controller = "Conversation", action = "GetConversation", conversationId = RouteParameter.Optional, lastMessageId = RouteParameter.Optional}
);

Web API 2中的替代方法是在WebApiConfig中删除自定义路由配置，并使用Route属性。

public class MessageController : ApiController
{
    [HttpGet]
    [Route("api/Message/PaginateMessages/{conversationId}/{lastMessageId}")]
    public async Task<List<MessageDTO>> PaginateMessages(
         int conversationId, int lastMessageId)
    {
        return null;
    }
}

具有多个参数404的Web Api路线

1 个答案: