大家好,
我有这个访客表:
ID | Date | Purpose
1 | 20/10/2016 | Purpose1
2 | 22/10/2016 | Purpose1
3 | 25/10/2016 | Purpose2
4 | 12/11/2016 | Purpose1
5 | 14/11/2016 | Purpose2
6 | 16/11/2016 | Purpose2
目前我正在使用此查询:
select case
when date like '%/10/2016' then '10/2016'
when date like '%/11/2016' then '11/2016'
end as month, count(*) as total
from visitors
where
date like '%/10/2016'
or date like '%/11/2016'
GROUP by month
我只能从上面的查询中获得月份和总列数。我怎样才能实现这个输出?
Month | Total | Purpose1 | Purpose2
10/2016 | 3 | 2 | 1
11/2016 | 3 | 1 | 2
谢谢!
答案 0 :(得分:0)
转置表格并不是非常快。最好在一些小程序中这样做。
如果你做了
select case
when date like '%/10/2016' then '10/2016'
when date like '%/11/2016' then '11/2016'
end as month, count(*) as total, Purpose
from visitors
where
date like '%/10/2016'
or date like '%/11/2016'
GROUP by month, Purpose
你有一个很好的起点。 您可能需要添加ORDER BY子句(取决于您的DBMS)。
如果(且仅当)你的表中只有两个目的而且表格的大小不大,你可以创建两个视图并加入它们。
答案 1 :(得分:0)
考虑以下内容......
DROP TABLE IF EXISTS my_table;
CREATE TABLE my_table
(ID INT NOT NULL AUTO_INCREMENT PRIMARY KEY
,Date DATE NOT NULL
,Purpose VARCHAR(12) NOT NULL
);
INSERT INTO my_table VALUES
(1,'2016-10-20','Purpose1'),
(2,'2016-10-22','Purpose1'),
(3,'2016-10-25','Purpose2'),
(4,'2016-11-12','Purpose1'),
(5,'2016-11-14','Purpose2'),
(6,'2016-11-16','Purpose2');
SELECT DATE_FORMAT(date,'%Y-%m') month
, SUM(purpose = 'purpose1') purpose1
, SUM(purpose = 'purpose2') purpose2
, COUNT(*) total
FROM my_table
GROUP
BY month;
+---------+----------+----------+-------+
| month | purpose1 | purpose2 | total |
+---------+----------+----------+-------+
| 2016-10 | 2 | 1 | 3 |
| 2016-11 | 1 | 2 | 3 |
+---------+----------+----------+-------+
..或(在我看来,如果您可以访问应用程序代码,那就更好了......)
SELECT DATE_FORMAT(date,'%Y-%m') month
, purpose
, COUNT(*) total
FROM my_table
GROUP
BY month
, purpose;
+---------+----------+-------+
| month | purpose | total |
+---------+----------+-------+
| 2016-10 | Purpose1 | 2 |
| 2016-10 | Purpose2 | 1 |
| 2016-11 | Purpose1 | 1 |
| 2016-11 | Purpose2 | 2 |
+---------+----------+-------+