Question

我有以下查询：

SELECT coalesce(COUNT('view_id'),0) level1count,y,m
    from
    (select 1 as m,2016 as y
    union
    select 2 as m,2016 as y
    union
    select 3 as m,2016 as y
    union
    select 4 as m,2016 as y
    union
    select 5 as m,2016 as y
    union
    select 6 as m,2016 as y
    union
    select 7 as m,2016 as y
    union
    select 8 as m,2016 as y
    union
    select 9 as m,2016 as y
    union
    select 10 as m,2016 as y
    union
    select 11 as m,2016 as y
    union
    select 12 as m ,2016 as y
    ) months
    left join page_views on(months.m = month(page_views.view_date) and months.y = year(page_views.view_date))
    group by months.m, year(page_views.view_date)

结果如下：

level1count    Year    Month
-----------------------------------------
1              2016    1
1              2016    2
1              2016    3
1              2016    4
34             2016    5
1392           2016    6
49             2016    7
1095           2016    8
1173           2016    9
859            2016    10
605            2016    11
100            2016    12

我需要像这样显示level1count：

1,1,1,1,34,1392,49,1095,1173,859,605,100

使用PHP - 我是新手并在其中开发网站。我想也许它需要放在一个数组然后以某种方式回应？

很抱歉，如果这是一个愚蠢的问题，但就像我说的那样 - 对PHP非常新，并慢慢掌握它。

非常感谢

JS

Answer 1

这样可以解决问题：

<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";

// Create connection
$db_connection = new mysqli($servername, $username, $password, $dbname);

// Check connection
if ($db_connection->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 

$sql = "your query here";
$result = $db_connection->query($sql);
$arrLevel1 = [];

if ($result->num_rows > 0) {
    while($row = $result->fetch_assoc()) {
        array_push($arrLevel1, $row['level1count'];

} else {
    echo "0 results";
}
$comma_separated = implode(",", $arrLevel1);
echo $comma_separated;
$conn->close();
?>

*请记住，查询只是让事情变得简单的一个例子。它不安全，允许sql注入。

将以下查询显示为逗号分隔列表

1 个答案: