Question

如果我在文本文件中的列表具有以下内容

我希望它打印出来像

然而，我当前的代码将其打印出来，如

我的代码是：

#import "UIImage+Resizing.h"

@implementation UIImage (Resizing)

-(UIImage*)resizedImageWithSize:(CGSize)size {


    CGImageRef cgImage = [self CGImage];

    size_t bitsPerComponent = CGImageGetBitsPerComponent(cgImage);
    size_t bytesPerRow = CGImageGetBytesPerRow(cgImage);
    CGColorSpaceRef colorSpace = CGImageGetColorSpace(cgImage);
    CGBitmapInfo bitmapInfo = CGImageGetBitmapInfo(cgImage);

    CGContextRef context = CGBitmapContextCreate(nil, size.width, size.height, bitsPerComponent, bytesPerRow, colorSpace, bitmapInfo);

    CGContextSetInterpolationQuality(context, kCGInterpolationHigh);

    CGContextDrawImage(context, CGRectMake(0, 0, size.width, size.height), cgImage);

    CGImageRef resizedImageRef = CGBitmapContextCreateImage(context);

    UIImage *resizedImage = [UIImage imageWithCGImage:resizedImageRef];

    CFRelease(resizedImageRef);
    CFRelease(context);

    return resizedImage;

}

@end

如何切换名称最后两部分的顺序？我的代码在哪个区域错了，因为我不确定如何逆转它。如果我在反转函数之后添加一个print语句，它会将名称的每个部分分隔为一个字符串，但是当它加入时，它会以错误的顺序执行

Answer 1

不要反转清单：

def addStudent(student):
    reg,year,degree,*name= student.strip().split()
    fullName = "%s, %s" % (name[-1], " ".join(name[:-1]))
    return (reg, year, degree, name, fullName)

Answer 2

或更改该行

fullName = name[0] + ", " + " ".join(name[1:])

到这个

fullName = name[0] + ", " + " ".join(name[-1:0:-1])

编辑：

dat = '1234567 1 C100 Bartholomew Homer Simpson'

def addStudent(student):
    reg,year,degree,*name= student.strip().split(" ")
    name = list(reversed(name))
#    You have now:: 
#        name = ['Simpson', 'Homer', 'Bartholomew']
#    Therefore , name[-1:0:-1]  
#        will select from last item in list 'Bartholomew to 
#        the 0th one, the 0th  being excluded in reverse   
    fullName = name[0] + ", " + " ".join(name[-1:0:-1])

    return (reg,year,degree,name,fullName)

def printStud(studentTuple):
    reg,year,degree,*name,fullName = studentTuple
    reg = int(reg)
    thisYear = "Year "+str(year)
    print(format(fullName, "<32s")+format(reg,"<7d")+format(degree,">6s"),format(thisYear,">6s"))

输出：

 In [1]:
 Simpson, Bartholomew Homer      1234567  C100 Year 1

Answer 3

如果您需要排序名称，可以使用sorted()

对其进行排序

a=["metallica", "therion", "acdc"]
print a[0],", "+" ".join( sorted(a[1:]))

出：

metallica，acdc therion

Python - 打印反向名称顺序

3 个答案: