Question

以前我遇到route precedence的问题有帮助和建议我通过在我的路线中添加正则表达式来克服它。现在我的路线是：

Route::get('/{country}/{category}', ['as' => 'tour.list', 'uses' => 'LinkController@tourlist'])
            ->where('country', '[A-Za-z]+')->where('category', '[A-Za-z]+');

Route::get('/{category}/{slug}',['as' => 'single.tour', 'uses' => 'LinkController@singleTour'])
            ->where('category', '[A-Za-z]+')->where('category', '[w\d\-\_]+');

使用此路由我收到错误：

Symfony \ Component \ HttpKernel \ Exception \ NotFoundHttpException

当我从第一条路线移除正则表达式时，我遇到了与之前相同的问题，当我从第二条路线移除正则表达式时，我收到错误：

Trying to get property of non-object 
(View: F:\project\resources\views\public\tours\show.blade.php)

我在LinkController中的方法是：

public function tourlist($country, $category){
$tour = Tour::whereHas('category', function($q) use($category) {
            $q->where('name','=', $category);
        })
        ->whereHas('country', function($r) use($country) {
            $r->where('name','=', $country);
        })
        ->get();
    return view('public.tours.list')->withTours($tour);
}

public function singleTour($slug,$category)
{
$tour = Tour::where('slug','=', $slug)
              ->whereHas('category', function($r) use($category) {
            $r->where('name','=', $category);
        })
        ->first();
   return view('public.tours.show')->withTour($tour);
}

我的代码是：

<a href="{{ route('single.tour',['category' => $tour->category->name, 'slug' => $tour->slug]) }}">{{$tour->title}}</a>

Answer 1

更改正则表达式

where('category', '[w\d\-\_]+');至where('slug', '[A-Za-z\d\-\_]+');

以上将解决路线无法正常工作的初始问题。

Laravel 5.3中的Symfony \ Component \ HttpKernel \ Exception \ NotFoundHttpException

1 个答案: