Question

scheduled_datetime

2016-12-07 10:30:00
2016-12-07 13:30:00
2016-11-06  22:30:00
2016-12-06  23:30:00
2016-19-08  22:30:00

如果日期相同则按日期排序第一个日期

select * 
from mytable 
where scheduled_datetime > now()  
order by scheduled_datetime;

从这个查询我必须找到比今天更大的日期，请告诉我哪里出错了。

Answer 1

您有以下3个选项：

--If you want to fetch records greater than current date & time
select * from mytable where scheduled_datetime > NOW()
--If you want to fetch records greater than current date
select * from mytable where scheduled_datetime > CURDATE()
--If you want to fetch records greater than current time
select * from mytable where scheduled_datetime > CURTIME()

您可以根据您想要获取数据的顺序使用ORDER BY ASC或DESC。

Answer 2

如果您只想输出大于今天的日期，则需要使用DATE()仅与scheduled_datetime的日期值进行比较：

select * 
from mytable 
where DATE(scheduled_datetime) > NOW()  
order by scheduled_datetime asc;

如何在mysql中对Date进行排序

2 个答案: