select a.test
from demotable b
,XMLTable('//test' passing xmltype(b.xmlTagColumn) columns test varchar(10) path '.') a
b.xmlTagColumn具有xml内容。
如果b.xmlTagColumn有<test></test>
,那么我从上面的语句中得不到任何东西,甚至不是null。如何为空标记获取空值或虚值?
答案 0 :(得分:1)
$scope.$watch("picFile", function(value) {
if (value) {
var photoSize = (value.size/1000000) <= 2 ;
var photoext = !(validPhoto(value.name));
if (!photoSize && !photoext) {
$scope.showPPicFlag = false;
angular.element('.helpmesspic').find('span')[0].style.color = "red";
angular.element('.helpmesspic').find('span')[1].style.color = "red";
angular.element('.uploadPhoto').prop('disabled', true);
} else if (!photoSize) {
$scope.showPPicFlag = false;
angular.element('.helpmesspic').find('span')[0].style.color = "red";
angular.element('.uploadPhoto').prop('disabled', true);
} else if ( !photoext) {
$scope.showPPicFlag = false;
angular.element('.helpmesspic').find('span')[1].style.color = "red";
angular.element('.uploadPhoto').prop('disabled', true);
} else {
$scope.showPPicFlag = true;
angular.element('.uploadPhoto').prop('disabled', false);
}
}
}, true);
left join ... on 1=1
演示
select a.test
from demotable b
left join XMLTable
(
'//test'
passing xmltype(b.xmlTagColumn)
columns
test varchar(10) path '.'
) a
on 1=1
;
create table demotable (id int,xmlTagColumn varchar2(100));
insert into demotable (id,xmlTagColumn) values (1,'<X><test>123</test></X>');
insert into demotable (id,xmlTagColumn) values (2,'<Y><test>456</test></Y>');
insert into demotable (id,xmlTagColumn) values (3,'<Z><prod>123</prod></Z>');
select b.id
,a.test
from demotable b
left join XMLTable
(
'//test'
passing xmltype(b.xmlTagColumn)
columns
test varchar(10) path '.'
) a
on 1=1
;