Question

我有一个清单＆lt; item＆gt;以下

public class Item
{
    public string Link { get; set; }
    public string Title { get; set; }
    public string Content { get; set; }
    public DateTime PublishDate { get; set; }
    public FeedType FeedType { get; set; }

    public Item()
    {
        Link = "";
        Title = "";
        Content = "";
        PublishDate = DateTime.Today;
        FeedType = FeedType.RSS;
    }
}

这只是一个已解析的RSS提要，我现在希望能够查询List＆lt; item＆gt;仅使用今天的PublishDate提取项目？

但是我有点迷失了......有人可以放任何光吗？

Answer 1

如果我理解正确，这里的目标是在比较时剥离时间。

扩展方法语法

var today = DateTime.Today;
items.Where( item => item.PublishDate.Date == today );

查询语法

var today = DateTime.Today;
from item in items
where item.PublishDate.Date == Today
select item

Answer 2

DateTime today = DateTime.Today;
var todayItems = list.Where(item => item.PublishDate.Date == today);

Answer 3

List<Item> itemList = ...;
ListItem<Item> filtered items 
                 = itemList.Where(it => it.PublishDate >= DateTime.Today).ToList()

使用Linq按日期获取数据

3 个答案: