python如何重构相反的数字子句

Question

如果可能，我想将以下两个条款（彼此完全相反）重构为一个：

if who == 0:
    score = take_turn(strategy0(score0, score1), score1, select_dice(score0, score1))
    if score == 0:
        score1 += strategy0(score0, score1)
    else:
        score0 += score
elif who == 1:
    score = take_turn(strategy1(score1, score0), score0, select_dice(score1, score0))
    if score == 0:
        score0 += strategy1(score1, score0)
    else:
        score1 += score

我如何才能实现以下目标？

def other(who)
    return 1 - who

score = take_turn(strategy+who(score+who, score+other), score+other, select_dice(score+who, score+other))
if score == 0:
    score+other += strategy+who(score+who, score+other)
else:
    score+who += score

Answer 1

您的代码很复杂，因为您分散了相关的数据。

所以你要做的就是收集数据并将其作为参数传递。

有一些可能的场景，我将使用字典来代码。

dataWho = {"id": 0, "score": score0, "strategy": strategy0}  #gathering related data. function also can be the value of dictionary.
dataOther = {"id": 1, "score": score1, "strategy": strategy1}

def foo(dataWho, dataOther):
    score = take_turn(dataWho["strategy"](dataWho["score"], dateOther["score"]), dataOther["score"], select_dice(dataWho["score"], dateOther["score"]))
    if score == 0:
        dateOther["score"] += dataWho["stratey"](dataWho["score"], dateOther["score"])
    else:
        dataWho["score"] += score

我认为课程实施更好，你应该尝试。