Question

我想从Java程序中获取EReference的值

我使用此库：https://github.com/tesis-dynaware/graph-editor

以下是生成的xmi文件的示例：

<?xml version="1.0" encoding="ASCII"?>
<graph:GModel xmi:version="2.0" xmlns:xmi="http://www.omg.org/XMI" xmlns:graph="http://de.tesis.dynaware.grapheditor.model/1.0">
  <nodes type="tree-node" x="1217.0" y="556.0">
    <connectors type="tree-output" connections="//@connections.0 //@connections.1" connectionDetachedOnDrag="false"/>
  </nodes>
  <nodes type="tree-node" x="1020.0" y="756.0">
    <connectors type="tree-input" connections="//@connections.0"/>
    <connectors type="tree-output" connectionDetachedOnDrag="false"/>
  </nodes>
  <nodes type="tree-node" x="1260.0" y="775.0">
    <connectors type="tree-input" connections="//@connections.1"/>
    <connectors type="tree-output" connectionDetachedOnDrag="false"/>
  </nodes>
  <connections type="tree-connection" source="//@nodes.0/@connectors.0" target="//@nodes.1/@connectors.0"/>
  <connections type="tree-connection" source="//@nodes.0/@connectors.0" target="//@nodes.2/@connectors.0"/>
</graph:GModel>

我想要的是获取EReference源的值，我必须得到例证：/@nodes.0/@connectors.0

我尝试了以下代码

GModel gModel=model;
      EList<GConnection> connections=gModel.getConnections();
      for(GConnection connection : connections)
      {
          GConnector source=connection.getSource();
          System.out.println(" valeur source =" +source);
      }

但我得到以下结果：

valeur source = de.tesis.dynaware.grapheditor.model.impl.GConnectorImpl@21dd34be（id：null，type：tree-output，x：0.0，y：0.0，connectionDetachedOnDrag：false）

Answer 1

在我再次阅读之后，我想我理解了你的问题。您是否尝试在特定位置获取实际EObject，例如：//@nodes.0/@connectors.0？此路径称为URIfragment。使用URIfragment，您可以从资源树的根目录获取存储在此位置的EObject。你需要把你的GModel放在emf org.eclipse.emf.ecore.resource.Resource中，如果还没有，你可以检查gModel.eResource()）

假设gModel.eResource() == null：

//create a new Resource
Resource resource = new ResourceImpl();
//add the gModel
resource.getContents().add(gModel);
//get the EObject from the URIfragment
GConnector connector = (GConnector)resource.getEObject("//@nodes.0/@connectors.0");

assert resource.getURIFragment(connector).equals("//@nodes.0/@connectors.0");

是否有可能通过名称获得EReference的价值？

1 个答案: