Question

我必须让这段代码返回相同的结果，但只有在userID是一个数字的地方（ex 16）; 每个设备在此表中都有一个用户标识和用户名。这是代码：

<?php 

$myQuery= 'SELECT * FROM devicesissued di LEFT JOIN usercred uc ON di.userID = uc.userID WHERE 1 ORDER BY timeStamp DESC';
$result = mysql_query($myQuery) or die($myQuery."<br/><br/>".mysql_error());
while($row = mysql_fetch_array($result)) 
{
    $catQuery = 'SELECT * FROM deviceinventory WHERE deviceID = '. $row['deviceID'];
    $catResult = mysql_query($catQuery) or die($catQuery."<br/><br/>".mysql_error());
    $cat = mysql_fetch_array($catResult);
  echo "<tr>";
  echo "<td>" . $row['displayName'] . "</td>";
  echo "<td>" . $row['deviceID'] . "</td>";
  echo "<td>" . $cat['barCodeID'] . "</td>";
  echo "<td>" . $cat['category'] . "</td>";
  echo "<td>" . $row['deviceName'] . "</td>";
  echo "<td>" . $cat['operatingSystem'] . "</td>";
  echo "<td>" . $cat['serialNumber'] . "</td>";
  echo "<td>" . $cat['macAddress'] . "</td>";
  echo "<td>" . $row['timeStamp'] . "</td>";
  echo "</tr>";
}

?>

如果我添加WHERE 'userID' = A-Number条款，它就不会做任何事情。

如果您有任何想法，我将很乐意尝试。

谢谢。

Answer 1

尝试稍微更改您的查询

query_values

由于您在两个连接表（$myQuery= 'SELECT * FROM devicesissued di LEFT JOIN usercred uc ON di.userID = uc.userID WHERE di.userID=the_number_here ORDER BY timeStamp DESC';和deviceissued）中都有userID，因此您必须告诉MySQL您要在哪个表上执行usercred - 子句。

PHP＆amp; MySQL，获取表

1 个答案: